Open a raw file descriptor to access data under a URI. This interacts with the underlying ContentProvider.OpenAssetFile(Android.Net.Uri, System.String) method of the provider associated with the given URI, to retrieve any file stored there.

Accepts the following URI schemes:

• content (ContentResolver.SchemeContent)
• android.resource (ContentResolver.SchemeAndroidResource)
• file (ContentResolver.SchemeFile)

The android.resource (ContentResolver.SchemeAndroidResource) Scheme

A Uri object can be used to reference a resource in an APK file. The Uri should be one of the following formats:

• android.resource://package_name/id_number
  
  package_name is your package name as listed in your AndroidManifest.xml. For example com.example.myapp
  
  id_number is the int form of the ID.
  
  The easiest way to construct this form is

  java Example

  Uri uri = Uri.parse("android.resource://com.example.myapp/" + R.raw.my_resource");

• android.resource://package_name/type/name
  
  package_name is your package name as listed in your AndroidManifest.xml. For example com.example.myapp
  
  type is the string form of the resource type. For example, raw or drawable. name is the string form of the resource name. That is, whatever the file name was in your res directory, without the type extension. The easiest way to construct this form is

  java Example

  Uri uri = Uri.parse("android.resource://com.example.myapp/raw/my_resource");

Note that if this function is called for read-only input (mode is "r") on a content: URI, it will instead call ContentResolver.OpenTypedAssetFileDescriptor(Android.Net.Uri, System.String, System.String) for you with a MIME type of "*/*". This allows such callers to benefit from any built-in data conversion that a provider implements.

[Android Documentation]