Remember if you just want the days in the current month, use the date function:
$days = date("t");
(PHP 4 >= 4.1.0, PHP 5, PHP 7)
cal_days_in_month — Return the number of days in a month for a given year and calendar
$calendar
, int $month
, int $year
)
This function will return the number of days in the
month of year for
the specified calendar.
calendarCalendar to use for calculation
monthMonth in the selected calendar
yearYear in the selected calendar
The length in days of the selected month in the given calendar
Example #1 cal_days_in_month() example
<?php
$number = cal_days_in_month(CAL_GREGORIAN, 8, 2003); // 31
echo "There were {$number} days in August 2003";
?>
Remember if you just want the days in the current month, use the date function:
$days = date("t");
Forgot to compile the calendar plugin in... Wrote a workaround while I waited for it to compile. It only supports the Gregorian calendar.
<?php
if (!function_exists('cal_days_in_month'))
{
function cal_days_in_month($calendar, $month, $year)
{
return date('t', mktime(0, 0, 0, $month, 1, $year));
}
}
if (!defined('CAL_GREGORIAN'))
define('CAL_GREGORIAN', 1);
?>
Here's a one-line function I just wrote to find the numbers of days in a month that doesn't depend on any other functions.
The reason I made this is because I just found out I forgot to compile PHP with support for calendars, and a class I'm writing for my website's open source section was broken. So rather than recompiling PHP (which I will get around to tomorrow I guess), I just wrote this function which should work just as well, and will always work without the requirement of PHP's calendar extension or any other PHP functions for that matter.
I learned the days of the month using the old knuckle & inbetween knuckle method, so that should explain the mod 7 part. :)
<?php
/*
* days_in_month($month, $year)
* Returns the number of days in a given month and year, taking into account leap years.
*
* $month: numeric month (integers 1-12)
* $year: numeric year (any integer)
*
* Prec: $month is an integer between 1 and 12, inclusive, and $year is an integer.
* Post: none
*/
// corrected by ben at sparkyb dot net
function days_in_month($month, $year)
{
// calculate number of days in a month
return $month == 2 ? ($year % 4 ? 28 : ($year % 100 ? 29 : ($year % 400 ? 28 : 29))) : (($month - 1) % 7 % 2 ? 30 : 31);
}
?>
Enjoy,
David Bindel
If you have a DateTime variable you want to find the number of days in the month for, you can simply use $dt->format and the format specifiers 'm' and 'Y' to get the month digit, and year to use with cal_days_in_month eg.
function DaysInMonth($dt) {
$m = $dt->format('m');
$y = $dt->format('Y');
$numDays = cal_days_in_month (CAL_GREGORIAN, $m,$y);
return $numDays;
}
Function for calculation number of days until birthday:
<?php
function daysLeftForBirthday($devabirthdate)
{
/* input birthday date format -> Y-m-d */
list($y, $m, $d) = explode('-',$devabirthdate);
$nowdate = mktime(0, 0, 0, date("m"), date("d"), date("Y"));
$nextbirthday = mktime(0,0,0,$m, $d, date("Y"));
if ($nextbirthday<$nowdate)
$nextbirthday=$nextbirthday+(60*60*24*365);
$daycount=intval(($nextbirthday-$nowdate)/(60*60*24));
return $daycount;
}
?>
This will work great in future dates but will give the wrong answer for dates before 1550 (approx) when leap year was introduced and the calendar lost a year or two.
Sorry now to be more specific it has been a while sine I had to account for those later dates and had to take that into account but just a heads up for others to watch out.
<?php
# PHP Calendar (version 2.3), written by Keith Devens
function generate_calendar($year, $month, $days = array(), $day_name_length = 3, $month_href = NULL, $first_day = 0, $pn = array()){
$first_of_month = gmmktime(0,0,0,$month,1,$year);
#remember that mktime will automatically correct if invalid dates are entered
# for instance, mktime(0,0,0,12,32,1997) will be the date for Jan 1, 1998
# this provides a built in "rounding" feature to generate_calendar()
$day_names = array(); #generate all the day names according to the current locale
for($n=0,$t=(3+$first_day)*86400; $n<7; $n++,$t+=86400) #January 4, 1970 was a Sunday
$day_names[$n] = ucfirst(gmstrftime('%A',$t)); #%A means full textual day name
list($month, $year, $month_name, $weekday) = explode(',',gmstrftime('%m,%Y,%B,%w',$first_of_month));
$weekday = ($weekday + 7 - $first_day) % 7; #adjust for $first_day
$title = htmlentities(ucfirst($month_name)).' '.$year; #note that some locales don't capitalize month and day names
#Begin calendar. Uses a real <caption>. See http://diveintomark.org/archives/2002/07/03
@list($p, $pl) = each($pn); @list($n, $nl) = each($pn); #previous and next links, if applicable
if($p) $p = '<span class="calendar-prev">'.($pl ? '<a href="'.htmlspecialchars($pl).'">'.$p.'</a>' : $p).'</span> ';
if($n) $n = ' <span class="calendar-next">'.($nl ? '<a href="'.htmlspecialchars($nl).'">'.$n.'</a>' : $n).'</span>';
$calendar = '<table class="calendar">'."\n".
'<caption class="calendar-month">'.$p.($month_href ? '<a href="'.htmlspecialchars($month_href).'">'.$title.'</a>' : $title).$n."</caption>\n<tr>";
if($day_name_length){ #if the day names should be shown ($day_name_length > 0)
#if day_name_length is >3, the full name of the day will be printed
foreach($day_names as $d)
$calendar .= '<th abbr="'.htmlentities($d).'">'.htmlentities($day_name_length < 4 ? substr($d,0,$day_name_length) : $d).'</th>';
$calendar .= "</tr>\n<tr>";
}
if($weekday > 0) $calendar .= '<td colspan="'.$weekday.'"> </td>'; #initial 'empty' days
for($day=1,$days_in_month=gmdate('t',$first_of_month); $day<=$days_in_month; $day++,$weekday++){
if($weekday == 7){
$weekday = 0; #start a new week
$calendar .= "</tr>\n<tr>";
}
if(isset($days[$day]) and is_array($days[$day])){
@list($link, $classes, $content) = $days[$day];
if(is_null($content)) $content = $day;
$calendar .= '<td'.($classes ? ' class="'.htmlspecialchars($classes).'">' : '>').
($link ? '<a href="'.htmlspecialchars($link).'">'.$content.'</a>' : $content).'</td>';
}
else $calendar .= "<td>$day</td>";
}
if($weekday != 7) $calendar .= '<td colspan="'.(7-$weekday).'"> </td>'; #remaining "empty" days
return $calendar."</tr>\n</table>\n";
}
echo generate_calendar(2010, 12, 16,3,NULL,0,15, $first_of_month, $day_names, $day_names[$n]);
#echo generate_calendar($year, $month, $days,$day_name_length,$month_href,$first_day,$pn);
?>
You can also use the date() function to get the number of days in a month. You can also pass the 2nd param strtotime() and specify a specific date:
date('t');
To get the number of days in a given month, you just need to pass a timestamp that occurs during that month to the date function.
I've found this is beneficial when I cannot guarantee a particular set of functionality has been compiled into a given PHP installation.
<?php
$month = "2"
$year = "2014"
date("t",mktime(0,0,0,$month,1,$year));
//equivalent to
date("t",mktime(0,0,0,2,1,2014));
//returns 28
?>
count specific days in a month like how many satureday in a monday or how many mondays in a month
<?php
function my_cal_days_in_month($year,$month,$calday="1"){ //0 Sunday, 1 Monday, 2 Tue , 3 Wed , 4. Thu , 5. Fri , 6. Sat
// calculate total number of occurance in this month
$num = cal_days_in_month(CAL_GREGORIAN, $month, $year); // days in month
$dayofweek = date( "w", mktime(0, 0, 0, $month, 1, $year));
$adddays=0;
if($calday > $dayofweek )
$adddays=1 + $calday - $dayofweek;
else if($calday < $dayofweek )
$adddays=1 + 7 + ($calday - $dayofweek );
$remainingdays=$num-$adddays;
$leavesnum=1+intval($remainingdays / 7);
return $leavesnum;
}
$year=2013;
$month=7;
$day=6;
echo my_cal_days_in_month($year,$month,$day);
Here is a nifty function to return the date for easter for ranges beyond 2037 or before 1970.
<?php
function str_easter_date ($year) {
$days = easter_days ($year);
$days_in_march = cal_days_in_month (CAL_GREGORIAN, 3, $year);
if (($days + 21) < $days_in_march) {
$month = "March";
$date = $days + 21;
} else {
$month = "April";
$date = ($days + 21) - $days_in_march;
}
return "$month $date, $year";
}
?>