PHP 7.0.6 Released

imagecolorallocatealpha

(PHP 4 >= 4.3.2, PHP 5, PHP 7)

imagecolorallocatealphaAllocate a color for an image

Description

int imagecolorallocatealpha ( resource $image , int $red , int $green , int $blue , int $alpha )

imagecolorallocatealpha() behaves identically to imagecolorallocate() with the addition of the transparency parameter alpha.

Parameters

image

An image resource, returned by one of the image creation functions, such as imagecreatetruecolor().

red

Value of red component.

green

Value of green component.

blue

Value of blue component.

alpha

A value between 0 and 127. 0 indicates completely opaque while 127 indicates completely transparent.

The red, green and blue parameters are integers between 0 and 255 or hexadecimals between 0x00 and 0xFF.

Return Values

A color identifier or FALSE if the allocation failed.

Warning

This function may return Boolean FALSE, but may also return a non-Boolean value which evaluates to FALSE. Please read the section on Booleans for more information. Use the === operator for testing the return value of this function.

Changelog

Version Description
5.1.3 Returns FALSE if the allocation failed. Previously -1 was returned.

Examples

Example #1 Example of using imagecolorallocatealpha()

<?php
$size 
300;
$image=imagecreatetruecolor($size$size);

// something to get a white background with black border
$back imagecolorallocate($image255255255);
$border imagecolorallocate($image000);
imagefilledrectangle($image00$size 1$size 1$back);
imagerectangle($image00$size 1$size 1$border);

$yellow_x 100;
$yellow_y 75;
$red_x    120;
$red_y    165;
$blue_x   187;
$blue_y   125;
$radius   150;

// allocate colors with alpha values
$yellow imagecolorallocatealpha($image255255075);
$red    imagecolorallocatealpha($image2550075);
$blue   imagecolorallocatealpha($image0025575);

// drawing 3 overlapped circle
imagefilledellipse($image$yellow_x$yellow_y$radius$radius$yellow);
imagefilledellipse($image$red_x$red_y$radius$radius$red);
imagefilledellipse($image$blue_x$blue_y$radius$radius$blue);

// don't forget to output a correct header!
header('Content-Type: image/png');

// and finally, output the result
imagepng($image);
imagedestroy($image);
?>

The above example will output something similar to:

Output of example : Example of using imagecolorallocatealpha()

Notes

Note: This function requires GD 2.0.1 or later (2.0.28 or later is recommended).

See Also

User Contributed Notes

eric (at) junioronline.us
10 years ago
If you only wish to extract the alpha value for a color, you can simply extract it like so:

<?php

    $color
= imagecolorat($im, 50, 50);
   
$alpha = $color >> 24;

?>

It actually shifts off the first 24 bits (where 8x3 are used for each color), and returns the remaining 7 allocated bits (commonly used for alpha)
hosh [underscore] 90 [at] live [dot] com
5 years ago
I have had a case where I got the alpha from a raw RGBA pallete. This was stored as 8bit where 0 is completely transparant, and 255 is complete opaque.
This is impossible to use with imagecolorallocatealpha() as it requires a 7bit int where 0 is completely opaque and 127 is completely transparant (otherway around)
You can solve this by subtracting 255, removing the negative sign (either by converting to string and substr($alpha, 1) or some other way) and then bitshifting the answer to the right by one 1 bit.

Example:
<?php
$alpha
= 0; // equivalent to alpha 127 needed for imagecolorallocatealpha()
$alpha = $alpha - 255; // subtract 255, this will give a negative number
$alpha = substr($alpha, 1); // remove negative/minus sign
$alpha = (int)$alpha; // convert back to integer
$alpha = $alpha >> 1; // bitshift to the right once.
echo $alpha; // output: 127

// This can be done in one line of course:
$alpha = 255; // equivalent to 0 for imagecolorallocatealpha()
$alpha = ((int)(substr($alpha - 255, 1))) >> 1;
echo
$alpha; // outputs 0
?>
Ben Zemm
4 years ago
"This was stored as 8bit where 0 is completely transparant, and 255 is complete opaque."

This would be a lot more efficient:

<?php
$alpha7
= ((~((int)$alpha8)) & 0xff) >> 1;
?>

where alpha8==255, alpha7==0
where alpha8=127, alpha7== 64
where alpha8==0, alpha7==127
fjoggen at gmail dot com
8 years ago
If you need to calculate the integer representation of a color with an alpha channel, without initialising an image and using the imagecolorallocatealpha function. Then this function might be of some help:

<?php
function alphaColor($hexColor,$alpha)
{
        return
bindec(decbin($alpha).decbin(hexdec($hexColor));
}

echo
alphaColor("FFFFFF",127);
?>
Brett G
7 months ago
When working with transparency, avoid imagecreate() and use imagecreatetruecolor() instead. Transparency effects may not work as expected within a palette-based image.
fchristl at hotmail dot com
12 years ago
Check out this Source, it's a little funny feature showing you, for what imagecolorallocatealpha() is used:

<?php
$im
=imagecreatetruecolor(300,300);
$white=imagecolorallocate($im,255,255,255);
imagefilledrectangle($im,0,0,imagesx($im),imagesy($im),$white);
for(
$i=0;$i<256;$i=$i+10)
{
$col=imagecolorallocatealpha($im,$i,$i,$i,ceil(rand(0,127)));
imagefilledellipse($im,$i,$i,$i,$i,$col);
}
header("content-type: image/png");
imagepng($im);
?>
To Top