PHP 7.0.6 Released

    is_int

    (PHP 4, PHP 5, PHP 7)

    is_int — Find whether the type of a variable is integer

    Description

    bool is_int ( mixed $var )

    Finds whether the type of the given variable is integer.

    Note:

    To test if a variable is a number or a numeric string (such as form input, which is always a string), you must use is_numeric().

    Parameters

    var

    The variable being evaluated.

    Return Values

    Returns TRUE if var is an integer, FALSE otherwise.

    Examples

    Example #1 is_int() example

    <?php
    $values     = array(23, "23", 23.5, "23.5", null, true, false);
    foreach (    $values as $value) {
        echo     "is_int(";
            var_export($value);
        echo     ") = ";
            var_dump(is_int($value));
    }
    ?>

    The above example will output:

    is_int(23) = bool(true)
is_int('23') = bool(false)
is_int(23.5) = bool(false)
is_int('23.5') = bool(false)
is_int(NULL) = bool(false)
is_int(true) = bool(false)
is_int(false) = bool(false)

    See Also

    • is_bool() - Finds out whether a variable is a boolean
    • is_float() - Finds whether the type of a variable is float
    • is_numeric() - Finds whether a variable is a number or a numeric string
    • is_string() - Find whether the type of a variable is string
    • is_array() - Finds whether a variable is an array
    • is_object() - Finds whether a variable is an object

    User Contributed Notes

    Simon Neaves
    8 years ago
    I've found that both that is_int and ctype_digit don't behave quite as I'd expect, so I made a simple function called isInteger which does. I hope somebody finds it useful.

    <?php
    function isInteger($input){
        return(    ctype_digit(strval($input)));
    }

    var_dump(is_int(23)); //bool(true)
    var_dump(is_int("23")); //bool(false)
    var_dump(is_int(23.5)); //bool(false)
    var_dump(is_int(NULL)); //bool(false)
    var_dump(is_int("")); //bool(false)

    var_dump(ctype_digit(23)); //bool(true)
    var_dump(ctype_digit("23")); //bool(false)
    var_dump(ctype_digit(23.5)); //bool(false)
    var_dump(ctype_digit(NULL)); //bool(false)
    var_dump(ctype_digit("")); //bool(true)

    var_dump(isInteger(23)); //bool(true)
    var_dump(isInteger("23")); //bool(true)
    var_dump(isInteger(23.5)); //bool(false)
    var_dump(isInteger(NULL)); //bool(false)
    var_dump(isInteger("")); //bool(false)
    ?>
    andre dot roesti at 7flex dot net
    5 years ago
    With this function you can check if every of multiple variables are int. This is a little more comfortable than writing 'is_int' for every variable you've got.

    <?php
    function are_int ( ) {
            $args = func_get_args ();
        foreach (     $args as $arg )
            if ( !     is_int ( $arg ) )
                return     false;
        return     true;
    }

    // Example:
    are_int ( 4, 9 ); // true
    are_int ( 22, 08, 'foo' ); // false
    ?>
    e dot sand at elisand dot com
    7 years ago
    Simon Neaves was close on explaining why his function is perfect choice for testing for an int (as possibly most people would need).  He made some errors on his ctype_digit() output though - possibly a typo, or maybe a bug in his version of PHP at the time.

    The correct output for parts of his examples should be:

    <?php
    var_dump    (ctype_digit(23)); //bool(false)
    var_dump(ctype_digit("23")); //bool(true)
    var_dump(ctype_digit(23.5)); //bool(false)
    var_dump(ctype_digit(NULL)); //bool(false)
    var_dump(ctype_digit("")); //bool(false)
    ?>

    As you can see, the reason why using *just* ctype_digit() may not always work is because it only returns TRUE when given a string as input - given a number value and it returns FALSE (which may be unexpected).
    Robin
    6 years ago
    Keep in mind that is_int() operates in signed fashion, not unsigned, and is limited to the word size of the environment php is running in.

    In a 32-bit environment:

    <?php
    is_int    ( 2147483647 );           // true
    is_int( 2147483648 );           // false
    is_int( 9223372036854775807 );  // false
    is_int( 9223372036854775808 );  // false
    ?>

    In a 64-bit environment:

    <?php
    is_int    ( 2147483647 );           // true
    is_int( 2147483648 );           // true
    is_int( 9223372036854775807 );  // true
    is_int( 9223372036854775808 );  // false
    ?>

    If you find yourself deployed in a 32-bit environment where you are required to deal with numeric confirmation of integers (and integers only) potentially breaching the 32-bit span, you can combine is_int() with is_float() to guarantee a cover of the full, signed 64-bit span:

    <?php
    $small     = 2147483647;         // will always be true for is_int(), but never for is_float()
    $big = 9223372036854775807;  // will only be true for is_int() in a 64-bit environment

    if( is_int($small) || is_float($small) );  // passes in a 32-bit environment
    if( is_int($big) || is_float($big) );      // passes in a 32-bit environment
    ?>
    petepostma at gmail dot spam dot com
    3 years ago
    There is a versa to the vice of this int only type check.

    is_int( $integer_type) will only return true, if the TYPE is int, not the value
    ctype_digit( $string_type) will only return true if the TYPE is string, and its value is INT

    therefore:
    return ( is_int($value) || ctype_digit($value) );
    nicolas dot giraud at actiane dot com
    3 years ago
    Just a shorter way to check if your variable is an int or a string containing a int without others digit than 0 to 9 :

    <?php
    $bool     = ( !is_int($value) ? (ctype_digit($value)) : true );

    $value = 42; //true
    $value = '42'; //true
    $value = '1e9'; //false
    $value = '0155'; //true
    $value = 0155; //true
    $value = 0xFF; //true while it's just the same as 255
    $value = '0xFF'; //false
    $value = 'a'; //false
    $value = array(); //false
    $value = array('5'); //false
    $value = array(5); false
    $value     = ''; //false
    $value = NULL; //false

    ?>

    Short & cool :)
    tudor at tudorholton dot com
    8 years ago
    Please note this from the Integer datatype page:

    "The size of an integer is platform-dependent, although a maximum value of about two billion is the usual value (that's 32 bits signed). PHP does not support unsigned integers. Integer size can be determined from PHP_INT_SIZE, maximum value from PHP_INT_MAX since PHP 4.4.0 and PHP 5.0.5."

    This is particularly important if you are doing validation of large keys or any number larger than 2,000,000,000 (e.g. telephone numbers)
    gabe at websaviour dot com
    12 years ago
    Although this can be inferred from the documentation, beware of numeric strings.  I ran into the problem in a MySQL app where I would either SELECT an INT PRIMARY KEY or INSERT a new record and use mysql_insert_id() to get the KEY before continuing onto the new section. 

    I used is_int() to make sure the subsequent queries wouldn't break when using the key variable.  Unfortunately I failed to realize that while mysql_insert_id() returns an int, mysql_result() always returns a string even if you are SELECTing from an INT field.

    Spent at least 30 minutes trying to figure out why existing records weren't getting linked, but new records would link fine.  I ended up using intval() on mysql_result() to make sure subsequent queries still always work.
    qlimmax at gmail dot com
    8 years ago
    function is_natural($natural,$zero=true)
    {
    if(ctype_digit($natural))
    {
        if($zero)
        {
            $natural_test=(int)$natural;
            if((string)$natural_test !== $natural) return false;
            else return true;
        }
        else return true;
    }
    else return false;   
    }

    true for ("0","1","2","3",...) false for("-1","01","adS","#@!$%^&*-...","0.7","0,7", "0x12",...)
    if $zero=false
    true for("0","00","1","01",...) false("-1","#@!$%^&*-...","adS","0.7","0,7", "0x12",...)
    Vasiliy Makogon
    23 days ago
    If you want detect integer of float values, which presents as pure int or float, and presents as string values, use this functions:

    <?php
    function isInteger($val)
    {
        if (!    is_scalar($val) || is_bool($val)) {
            return     false;
        }
        if (    is_float($val + 0) && ($val + 0) > PHP_INT_MAX) {
            return     false;
        }
        return     is_float($val) ? false : preg_match('~^((:?+|-)?[0-9]+)$~', $val);
    }

    function     isFloat($val)
    {
        if (!    is_scalar($val)) {
            return     false;
        }
        return     is_float($val + 0);
    }

    foreach ([
            '11111111111111111', 11111111111111111, // > PHP_INT_MAX - presents in PHP as float
            1, '10', '+1', '1.1', 1.1, .2, 2., '.2', '2.',
            '-2.', '-.2', null, [], true, false, 'string'
    ] as $value) {
        echo     $value . ':' . gettype($value) . ' is Integer? - '  . (isInteger($value) ? 'yes' : 'no') . PHP_EOL;
        echo     $value . ':' . gettype($value) . ' is Float? - '  . (isFloat($value) ? 'yes' : 'no') . PHP_EOL;
    }
    ?>
    davide dot renzi at gmail dot com
    4 months ago
    I've found a faster way of determining an integer.
    On my env, this method takes about half the time of using is_int().

    Cast the value then check if it is identical to the original.

    <?php
    if ( (int) $n !== $n ) {
        echo     'not is int';
    } else {
        echo     'is int';
    }
    ?>
    Anonymous
    1 year ago
    Sometimes, we need to validate if a DECIMAL returned by a SQL database is an int or not. DECIMAL always return .000 at end of the string.

    Then i use:
    <?php
    function isInteger($input){
    {
        if(    strpos($input,"."))
                $input=preg_replace("/\.$/","",rtrim(strval($input),"0"));
        return (    ctype_digit($input));
    }
    ?>
    lclkk at urbanvagabond dot net
    12 years ago
    I think the function below is a robust test for integers working on all datatypes. It works by first checking that a number can be evaluated numerically, and then secondly that the integer evaluation matches the original number.

    Test cases are included.

    <?
    function myIsInt ($x) {
        return (is_numeric($x) ? intval($x) == $x : false);
    }

    function Test($x) {
        echo "$x is " . ( myIsInt($x) ? ('an integer. The integer value is ' . intval($x)) : 'not an integer.');
        echo "\n";
    }

    echo "These should be integers...\n";
    Test(1);
    Test(5);
    Test(10);
    Test(10.0);
    Test(20.0);
    Test(-20.0);
    Test(0+4+4.5+4.5);
    Test("10.0");
    Test("+14");
    Test("-15");
    Test("0");

    echo "\nThese should not be integers...\n";
    Test(true); // watch out, this displays as '1'
    Test(false);
    Test("moose");
    Test("3.5");
    Test("-214235.5");
    Test(""); // empty string
    Test(array(1,2,3));
    Test(dir('.')); // object
    Test(null);
    ?>
    ing dot alpi at gmail dot com
    2 years ago
    Remember that some source of data always give a string data type.
    That's the case with cookies and $_GET.
    if you need to check against those values, try to convert them into numbers first.
    The easiest way of doing so is adding a zero before your var, just like:

    <?php
    $var     = '15'; // ...or $var = $_COOKIE['myvar'] or $var =
    $_GET['myvar']...

    is_int($var);  // now returns FALSE

    $var += 0;

    is_int($var);  // now returns TRUE
    ?>
    me at rexxars dot com
    6 years ago
    I was looking for the fastest way to check for an unsigned integer which supported large numbers like 4318943448871348 or 0xFFFFFFFF.

    Fastest I came up with is this:
    <?php
    function is_unsigned_int($val) {
        return     ctype_digit((string) $value));
    }
    ?>

    Will return true on 1515, 0xFFFFFFFF, '3515' and '1365158185855141'.
    Will return false on 0.1515, '415.4134' and '-616'.

    Be aware though, before PHP 5.1.0 this will return true on an empty string.

    According to my benchmarks this is about 30% faster than the regex ^\d+$.
    Ender at soldat dot nl
    10 years ago
    Be aware that is_numeric (mentioned in this article as the proper way to validate string numbers) also allows numbers in scientific and hexadecimal annotation. Thus DO NOT USE that function to validate user input that will be used as id number for in a query for example, this could cause mysql errors. Use ctype_digit instead.
    ludvig dot ericson at gmail dot com
    10 years ago
    I would like to say that is_int() is pretty helpfull when looking for neat proper ways to check functions that return either integers or booleans (false) on failure (strpos, socket_select, etc.)
    <?php
    function mySelect() {
        global     $someSockets;
            $ret = socket_select($someSockets, $o = array(), $e = array(), 0);
        if (!    $ret)
            return     is_int($ret);
            /* FURTHER PROCESSING HERE */
            return true;    // Return true if the function proceeded as expected.
    }
    ?>
    The point of doing this is that if you put this in a while() loopo, you'll break it when the select fails.
    <?php
    while (mySelect());
    ?>

    Hope you get the point
    - toxik
    Wryel Covo - ryryel[at]gmail[dot]com
    7 years ago
    <?php
    function onlyNumbers($string){
            //This function removes all characters other than numbers
        //Esta função limpa a url e conserva apenas os numeros
            $string = preg_replace("/[^0-9]/", "", $string);
        return (int)     $string;
    }

    echo     $test = onlyNumbers("as87d68a6db8a7d686dx8a6dx"); //2147483647
    echo "<br/>";
    echo     onlyNumbers("xn89d9x797d9a8x7-"); //899797987
    echo "<br/>";
    if(    is_int($test)){
        echo     "Is int ! - É inteiro !"; // This OK !
    } else {
        echo     "Not int ! - Não é inteiro";
    }
    ?>
    Julien Picalausa
    7 years ago
    To check if a string ($s) is a representation of an integer (including representations is scientific notation and negative numbers), you can use the following test, provided that you don't expect values that are out of bounds for an integer.

    is_numeric($s) && floatval($s) == intval(floatval($s))

    If the test returns true, the string is a representation of an integer.
    is_numeric (if it works as intended) protects from strings that are not proper numbers.
    The comparison filters anything that is non_integer

    If, for performance reasons, you want to avoid converting to float twice, it can also be written:
    is_numeric($s) && ($f = floatval($s)) == intval($f)

    If you plan to get values that cannot be representated with an integer and are ready to deal with a float, you can use floor instead of intval, as long as you are ready to deal with floats. Even so, that method will become unreliable when the precision of the float becomes insufficient for getting to the fractional part of the number
    arturs at indigo dot lv
    3 years ago
    Sometime needed check if string containing numbers is integer or not. Then I created this small function:
    <?php
    function is_integer2($v) {
          $i = intval($v);
      if (    "$i" == "$v") {
        return     TRUE;
      } else {
        return     FALSE;
      }
    }
    ?>
    leonix at motd dot ru
    7 years ago
    another_is_int() is almost perfect, but it treats boolean true as int because
    1 == (int) true == (string) true == '1'.

    Fixed version:

    <?php
    /**
    * Checks if the given value represents integer
    */
    function int_ok($val)
    {
        return (    $val !== true) && ((string)(int) $val) === ((string) $val);
    }
    ?>
    Roberto Rama
    6 years ago
    Use this instead if you wanna know if a string is explicitly a number:

    <?php

    function isint( $mixed )
    {
        return (     preg_match( '/^\d*$/'  , $mixed) == 1 );
    }

    var_export( isint( '123' ) ); //This will return true

    var_export( isint( 123 ) ); //This will return true

    var_export( isint( 'asd' ) ); //This will return false

    var_export( isint( '123asd123' ) ); //This will return false

    ?>
    mark at codedesigner dot nl
    7 years ago
    updated version from Simon Neaves

    <?php
    function isInteger($input){
      return     preg_match('@^[-]?[0-9]+$@',$input) === 1;
    }
    ?>

    this function checks if the string:
    - starts with a - sign (optional)
    - ends with 1 or more numeric chars
    thierryreeuwijk at hotmail dot com
    6 years ago
    If you only want integer values like 23 or 0155, or form/string integer values like "23" or "0155" to be valid, this should work just fine.

    <?php

            function int($int){
           
                // First check if it's a numeric value as either a string or number
                if(is_numeric($int) === TRUE){
               
                    // It's a number, but it has to be an integer
                    if((int)$int == $int){

                    return     TRUE;
                   
                    // It's a number, but not an integer, so we fail
                    }else{
               
                    return     FALSE;
                }
           
                // Not a number
                }else{
           
                return     FALSE;
            }
        }

        print(    "155".int(155)."<br>");
        print(    "15.5".int(15.5)."<br>");
        print(    "\"155\"".int("155")."<br>");
        print(    "\"15.5\"".int("15.5")."<br>");
        print(    "\"0155\"".int("0155")."<br>");
        print(    "\"I'm 155\"".int("I'm 155")."<br>");
        print(    "\"test\"".int("test")."<br>");
        print(    "\"\"".int(""));
    ?>

    The above returns:

    155        TRUE
    15.5       FALSE
    "155"      TRUE
    "15.5"     FALSE
    "0155"     TRUE
    "I'm 155"  FALSE
    "test"     FALSE
    ""         FALSE
    paulo dot koch at g_mail dot com
    7 years ago
    Don't over-engineer it.

    <?php
    function another_is_int($a){
        return ((string)     $a) === ((string)(int) $a);
    }
    ?>
    some at somewhere dot com
    2 years ago
    <?php
    // check if input is a valid number
    // first number must be 1 thru 9, followed by a number 0-9, no decimals
    // true for "1", "1000"
    // false for "01", "-1", "1.2"
    function isInteger($input){
      return     preg_match('@^[1-9][0-9]*$@',$input) === 1;
    }
    ?>
    PHPDev esurf er s >dot
    1 year ago
    This will check if something has an acceptable integer value, such as

    a string with int value like "1" or "1.0"
    a float with int value like 1.0
    an int like 12e5

    The same as is_numeric, but with integer values.

    <?php

            function isIntValued($var) {
            if(    is_numeric($var)) {
                    $var=(float)$var;
                return ((float)(int)    $var)===$var;
            }
            return     FALSE;
        }

    ?>
    felix dot b at outlook dot com
    1 year ago
    ((int)$foo === $foo) does exactly the same as is_int($foo), but is faster performancewise, because PHP has quite an overhead on function calls.

    As you can see the expression only returns true if the type (and value) of $foo is the same as int-casted $foo, which is only the case when foo is an int.

    This applies to all the other is* functions aswell.
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