is_subclass_of() works also with classes between the class of obj and the superclass.
example:
<?php
class A {};
class B extends A {};
class C extends B {};
$foo=new C();
echo ((is_subclass_of($foo,'A')) ? 'true' : 'false');
?>
echoes 'true' .
(PHP 4, PHP 5, PHP 7)
is_subclass_of — Checks if the object has this class as one of its parents or implements it.
Checks if the given object has the class
class_name as one of its parents or implements it.
objectA class name or an object instance. No error is generated if the class does not exist.
class_nameThe class name
allow_string
If this parameter set to false, string class name as object
is not allowed. This also prevents from calling autoloader if the class doesn't exist.
This function returns TRUE if the object object,
belongs to a class which is a subclass of
class_name, FALSE otherwise.
| Version | Description |
|---|---|
| 5.3.9 |
Added allow_string parameter
|
| 5.3.7 |
Added support for class_name to work with
interfaces
|
| 5.0.3 |
You may also specify the object parameter as a
string (the name of the class)
|
Example #1 is_subclass_of() example
<?php
// define a class
class WidgetFactory
{
var $oink = 'moo';
}
// define a child class
class WidgetFactory_Child extends WidgetFactory
{
var $oink = 'oink';
}
// create a new object
$WF = new WidgetFactory();
$WFC = new WidgetFactory_Child();
if (is_subclass_of($WFC, 'WidgetFactory')) {
echo "yes, \$WFC is a subclass of WidgetFactory\n";
} else {
echo "no, \$WFC is not a subclass of WidgetFactory\n";
}
if (is_subclass_of($WF, 'WidgetFactory')) {
echo "yes, \$WF is a subclass of WidgetFactory\n";
} else {
echo "no, \$WF is not a subclass of WidgetFactory\n";
}
// usable only since PHP 5.0.3
if (is_subclass_of('WidgetFactory_Child', 'WidgetFactory')) {
echo "yes, WidgetFactory_Child is a subclass of WidgetFactory\n";
} else {
echo "no, WidgetFactory_Child is not a subclass of WidgetFactory\n";
}
?>
The above example will output:
yes, $WFC is a subclass of WidgetFactory no, $WF is not a subclass of WidgetFactory yes, WidgetFactory_Child is a subclass of WidgetFactory
Example #2 is_subclass_of() using interface example
<?php
// Define the Interface
interface MyInterface
{
public function MyFunction();
}
// Define the class implementation of the interface
class MyClass implements MyInterface
{
public function MyFunction()
{
return "MyClass Implements MyInterface!";
}
}
// Instantiate the object
$my_object = new MyClass;
// Works since 5.3.7
// Test using the object instance of the class
if (is_subclass_of($my_object, 'MyInterface')) {
echo "Yes, \$my_object is a subclass of MyInterface\n";
} else {
echo "No, \$my_object is not a subclass of MyInterface\n";
}
// Test using a string of the class name
if (is_subclass_of('MyClass', 'MyInterface')) {
echo "Yes, MyClass is a subclass of MyInterface\n";
} else {
echo "No, MyClass is not a subclass of MyInterface\n";
}
?>
The above example will output:
Yes, $my_object is a subclass of MyInterface Yes, MyClass is a subclass of MyInterface
Note:
Using this function will use any registered autoloaders if the class is not already known.
is_subclass_of() works also with classes between the class of obj and the superclass.
example:
<?php
class A {};
class B extends A {};
class C extends B {};
$foo=new C();
echo ((is_subclass_of($foo,'A')) ? 'true' : 'false');
?>
echoes 'true' .
This might be useful to someone, so:
If you're using Autoload, you should be aware that this will attempt to autoload $classname if it isn't already loaded. I discovered this when I had something using is_subclass_of inside an error thrown by autoload, which then recursed until it ran out of memory.
It would appear that is_subclass_of is case insensitive unlike get_class in php5.
i.e.
<?php
class fooBar {}
class bar extends fooBar {}
assert(get_class(new fooBar()) == "fooBar");
assert(is_subclass_of(new bar(), "foobar") == true);
?>
i run across this while migrating some code from php4 to php5 and the code would only half-the-time break.
If you need something similar to is_subclass_of() to determine if a class implements an interface before instantiating it, use reflection:
<?php
interface A_Interface {}
class A implements A_Interface {}
$reflectionA = new ReflectionClass('A');
var_dump(
$reflectionA->implementsInterface('A_Interface')
);
?>
bool(true)
<?php
interface I {
}
class A implements I {
}
class B extends A {
}
if (is_subclass_of('A', 'I')) {
echo 'good<br>';
}
else {
echo 'bad<br>';
}
if (is_subclass_of('B', 'I')) {
echo 'good<br>';
}
else {
echo 'bad<br>';
}
if (is_subclass_of('B', 'A')) {
echo 'good<br>';
}
else {
echo 'bad<br>';
}
?>
result:
bad <- you must to describe intermediate class B to be good
good
good
For PHP4:
<?php
/** Returns whether specified class is subclass of the other class. */
function is_subclass($sClass, $sExpectedParentClass){
do if( $sExpectedParentClass === $sClass ) return true;
while( false != ($sClass = get_parent_class($sClass)) );
return false;
}
// Test:
class A {} class B extends A {} class C extends B {} echo (int) is_subclass('C', 'A');
?>