PHP 7.0.6 Released

jdtounix

(PHP 4, PHP 5, PHP 7)

jdtounixConvert Julian Day to Unix timestamp

Description

int jdtounix ( int $jday )

This function will return a Unix timestamp corresponding to the Julian Day given in jday or FALSE if jday is not inside the Unix epoch (Gregorian years between 1970 and 2037 or 2440588 <= jday <= 2465342 ). The time returned is localtime (and not GMT).

Parameters

jday

A julian day number between 2440588 and 2465342.

Return Values

The unix timestamp for the start of the given julian day.

See Also

  • unixtojd() - Convert Unix timestamp to Julian Day

User Contributed Notes

seb at carbonauts dot com
12 years ago
Remember that unixtojd() assumes your timestamp is in GMT, but jdtounix() returns a timestamp in localtime.

This fooled me a few times. 

So if you have:

$timestamp1 = time();
$timestamp2 = jdtounix(unixtojd($timestamp1));

Unless your localtime is the same as GMT, $timestamp1 will not equal $timestamp2.
fabio at llgp dot org
9 years ago
If you need an easy way to convert a decimal julian day to an unix timestamp you can use:

$unixTimeStamp = ($julianDay - 2440587.5) * 86400;

2440587.5 is the julian day at 1/1/1970 0:00 UTC
86400 is the number of seconds in a day
Anonymous
11 years ago
Warning: the calender functions involving julian day operations seem to ignore the decimal part of the julian day count.

This means that the returned date is wrong 50% of the time, since a julian day starts at decimal .5 .  Take care!!
Saeed Hubaishan
1 year ago
unixtojd() assumes that your timestamp is in GMT, but jdtounix() returns a timestamp in localtime.
so
<?php
$d1
=jdtogregorian(unixtojd(time()));
$d2= gmdate("m/d/Y");
$d3=date("m/d/Y");
?>
$d1 always equals $d2 but $d1 may differ from $d3
pipian at pipian dot com
12 years ago
Remember that UNIX timestamps indicate a number of seconds from midnight of January 1, 1970 on the Gregorian calendar, not the Julian Calendar.
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