PHP 7.0.6 Released

ImagickPixel::getColor

(PECL imagick 2.0.0)

ImagickPixel::getColorReturns the color

Description

array ImagickPixel::getColor ([ bool $normalized = false ] )

Returns the color described by the ImagickPixel object, as an array. If the color has an opacity channel set, this is provided as a fourth value in the list.

Parameters

normalized

Normalize the color values

Return Values

An array of channel values, each normalized if TRUE is given as param. Throws ImagickPixelException on error.

Examples

Example #1 Basic Imagick::getColor() usage

<?php

//Create an ImagickPixel with the predefined color 'brown'
$color = new ImagickPixel('brown');

//Set the color to have an alpha of 25%
$color->setColorValue(Imagick::COLOR_ALPHA64 256.0);

$colorInfo $color->getColor();

echo 
"Standard values".PHP_EOL;
print_r($colorInfo);

$colorInfo $color->getColor(true);

echo 
"Normalized values:".PHP_EOL;
print_r($colorInfo);

?>

The above example will output:

Standard values
Array
(
    [r] => 165
    [g] => 42
    [b] => 42
    [a] => 0
)
Normalized values:
Array
(
    [r] => 0.64705882352941
    [g] => 0.16470588235294
    [b] => 0.16470588235294
    [a] => 0.25000381475547
)
    

User Contributed Notes

roman
2 years ago
In case you use default un-normalized getColor value the alpha value will always be either 0 or 1.

If you want to use real full-range 0-1 alpha channel on your 24bit transparent images use the alpha value from the normalized one, even if you use the rest of unnormalized data.

To copy a 24bit png with real alpha transparency, you would have to do this:
<?php

$im
=new Imagick( 'image.png' );
$iterator=$im->getPixelIterator();
foreach (
$iterator as $row=>$pixels) {
    foreach (
$pixels as $column => $pixel ){
       
$un_color=$pixel->getColor(); //unnormalized color
       
$nor_color=$pixel->getColor(true); //normalized color
       
$pixel->setColor('rgba('.$un_color['r'].','.$un_color['g'].','.$un_color['b'].','.$nor_color['a'].')');
    }
}
?>

If you use 'a' (alpha) value from the unnormalized color there will only be binary transparency.
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