PHP 7.0.6 Released

    mysqli::query

    mysqli_query

    (PHP 5, PHP 7)

    mysqli::query -- mysqli_query — Performs a query on the database

    Description

    Object oriented style

    mixed mysqli::query ( string $query [, int $resultmode = MYSQLI_STORE_RESULT ] )

    Procedural style

    mixed mysqli_query ( mysqli $link , string $query [, int $resultmode = MYSQLI_STORE_RESULT ] )

    Performs a query against the database.

    For non-DML queries (not INSERT, UPDATE or DELETE), this function is similar to calling mysqli_real_query() followed by either mysqli_use_result() or mysqli_store_result().

    Note:

    In the case where you pass a statement to mysqli_query() that is longer than max_allowed_packet of the server, the returned error codes are different depending on whether you are using MySQL Native Driver (mysqlnd) or MySQL Client Library (libmysqlclient). The behavior is as follows:

    • mysqlnd on Linux returns an error code of 1153. The error message means "got a packet bigger than max_allowed_packet bytes".

    • mysqlnd on Windows returns an error code 2006. This error message means "server has gone away".

    • libmysqlclient on all platforms returns an error code 2006. This error message means "server has gone away".

    Parameters

    link

    Procedural style only: A link identifier returned by mysqli_connect() or mysqli_init()

    query

    The query string.

    Data inside the query should be properly escaped.

    resultmode

    Either the constant MYSQLI_USE_RESULT or MYSQLI_STORE_RESULT depending on the desired behavior. By default, MYSQLI_STORE_RESULT is used.

    If you use MYSQLI_USE_RESULT all subsequent calls will return error Commands out of sync unless you call mysqli_free_result()

    With MYSQLI_ASYNC (available with mysqlnd), it is possible to perform query asynchronously. mysqli_poll() is then used to get results from such queries.

    Return Values

    Returns FALSE on failure. For successful SELECT, SHOW, DESCRIBE or EXPLAIN queries mysqli_query() will return a mysqli_result object. For other successful queries mysqli_query() will return TRUE.

    Changelog

    Version Description
    5.3.0 Added the ability of async queries.

    Examples

    Example #1 mysqli::query() example

    Object oriented style

    <?php
    $mysqli     = new mysqli("localhost", "my_user", "my_password", "world");

    /* check connection */
    if ($mysqli->connect_errno) {
            printf("Connect failed: %s\n", $mysqli->connect_error);
        exit();
    }

    /* Create table doesn't return a resultset */
    if ($mysqli->query("CREATE TEMPORARY TABLE myCity LIKE City") === TRUE) {
            printf("Table myCity successfully created.\n");
    }

    /* Select queries return a resultset */
    if ($result = $mysqli->query("SELECT Name FROM City LIMIT 10")) {
            printf("Select returned %d rows.\n", $result->num_rows);

            /* free result set */
            $result->close();
    }

    /* If we have to retrieve large amount of data we use MYSQLI_USE_RESULT */
    if ($result = $mysqli->query("SELECT * FROM City", MYSQLI_USE_RESULT)) {

            /* Note, that we can't execute any functions which interact with the
           server until result set was closed. All calls will return an
           'out of sync' error */
            if (!$mysqli->query("SET @a:='this will not work'")) {
                printf("Error: %s\n", $mysqli->error);
        }
            $result->close();
    }

    $mysqli->close();
    ?>

    Procedural style

    <?php
    $link     = mysqli_connect("localhost", "my_user", "my_password", "world");

    /* check connection */
    if (mysqli_connect_errno()) {
            printf("Connect failed: %s\n", mysqli_connect_error());
        exit();
    }

    /* Create table doesn't return a resultset */
    if (mysqli_query($link, "CREATE TEMPORARY TABLE myCity LIKE City") === TRUE) {
            printf("Table myCity successfully created.\n");
    }

    /* Select queries return a resultset */
    if ($result = mysqli_query($link, "SELECT Name FROM City LIMIT 10")) {
            printf("Select returned %d rows.\n", mysqli_num_rows($result));

            /* free result set */
            mysqli_free_result($result);
    }

    /* If we have to retrieve large amount of data we use MYSQLI_USE_RESULT */
    if ($result = mysqli_query($link, "SELECT * FROM City", MYSQLI_USE_RESULT)) {

            /* Note, that we can't execute any functions which interact with the
           server until result set was closed. All calls will return an
           'out of sync' error */
            if (!mysqli_query($link, "SET @a:='this will not work'")) {
                printf("Error: %s\n", mysqli_error($link));
        }
            mysqli_free_result($result);
    }

    mysqli_close($link);
    ?>

    The above examples will output:

    Table myCity successfully created.
Select returned 10 rows.
Error: Commands out of sync;  You can't run this command now

    See Also

    User Contributed Notes

    NUNTIUS
    8 years ago
    This may or may not be obvious to people but perhaps it will help someone.

    When running joins in SQL you may encounter a problem if you are trying to pull two columns with the same name. mysqli returns the last in the query when called by name. So to get what you need you can use an alias.

    Below I am trying to join a user id with a user role. in the first table (tbl_usr), role is a number and in the second is a  text name (tbl_memrole is a lookup table). If I call them both as role I get the text as it is the last "role" in the query. If I use an alias then I get both as desired as shown below.

    <?php
    $sql     = "SELECT a.uid, a.role AS roleid, b.role,
                FROM tbl_usr a
                INNER JOIN tbl_memrole b
                ON a.role = b.id
                "    ;

        if (    $result = $mysqli->query($sql)) {
            while(    $obj = $result->fetch_object()){
                    $line.=$obj->uid;
                    $line.=$obj->role;
                    $line.=$obj->roleid;
            }
        }
            $result->close();
        unset(    $obj);
        unset(    $sql);
        unset(    $query);
       
    ?>
    In this situation I guess I could have just renamed the role column in the first table roleid and that would have taken care of it, but it was a learning experience.
    theyranos at gmail dot com
    5 years ago
    The cryptic "Couldn't fetch mysqli" error message can mean any number of things, including:

    1. You're trying to use a database object that you've already closed (as noted by ceo at l-i-e dot com). Reopen your database connection, or find the call to <?php mysqli_close($db); ?> or <?php $db->close(); ?> and remove it.
    2. Your MySQLi object has been serialized and unserialized for some reason. Define a wakeup function to re-create your database connection. http://php.net/__wakeup
    3. Something besides you closed your mysqli connection (in particular, see http://bugs.php.net/bug.php?id=33772)
    4. You mixed OOP and functional calls to the database object. (So, you have <?php $db->query() ?> in the same program as <?php mysqli_query($db) ?>).
    petrus.jvr
    5 years ago
    When calling multiple stored procedures, you can run into the following error: "Commands out of sync; you can't run this command now".
    This can happen even when using the close() function on the result object between calls.
    To fix the problem, remember to call the next_result() function on the mysqli object after each stored procedure call. See example below:

    <?php
    // New Connection
    $db = new mysqli('localhost','user','pass','database');

    // Check for errors
    if(mysqli_connect_errno()){
    echo     mysqli_connect_error();
    }

    // 1st Query
    $result = $db->query("call getUsers()");
    if(    $result){
             // Cycle through results
            while ($row = $result->fetch_object()){
                $user_arr[] = $row;
        }
            // Free result set
            $result->close();
            $db->next_result();
    }

    // 2nd Query
    $result = $db->query("call getGroups()");
    if(    $result){
             // Cycle through results
            while ($row = $result->fetch_object()){
                $group_arr[] = $row;
        }
             // Free result set
             $result->close();
             $db->next_result();
    }
    else echo(    $db->error);

    // Close connection
    $db->close();
    ?>
    registrations at jdfoxmicro dot com
    5 years ago
    I like to save the query itself in a log file, so that I don't have to worry about whether the site is live.

    For example, I might have a global function:

    <?php
    function UpdateLog ( $string , $logfile )  {
           $fh = fopen ( $logfile , 'a' );
           $fwrite ( $fh , strftime ('%F %T %z')." ".$string."\n";
           fclose ( $fh );
    }
    ?>

    Then in my mysql function error trapper, something like this:

    <?php
       $error_msg     = "Database error in [page].php / ";
           $error_msg .= mysqli_error ( $link )." / ";
           $error_msg .= $query;
           UpdateLog ( $error_msg , DB_ERROR_LOG_FILE );
    ?>

    I also include the remote IP, user agent, etc., but I left it out of these code samples.  And have it e-mail me when an error is caught, too.

    Jeff
    ahmed dot 3abdolah at gmail dot com
    1 year ago
    Hi, i created function that add  a new table using array , i work with it on my projects ...
    <?PHP
                           /* this function was learned from PHP.net */
    function array_keys_exist(&$key,array &$array){
                        $keys = split("\|",$key);
                    foreach(    $keys as $key_s){
                        if(    array_key_exists($key_s, $array)) return true;
                        }
                    return     false;
                }
    /*and this is my function */
    array_create_table(array &$array){
            if(    is_array($array)){
                   $key = "table|rows|values";   
                $info = "";
            if(    array_keys_exist($key,$array)){
            if(    is_array($array["rows"]) and is_array($array["values"]) ){
                                            
                if(    count($array["rows"]) == count($array["values"])) {
                            for(    $i=0; $i<=count($array["rows"]); $i++){
            $info = $info." ".$array["rows"][$i]." ".$array["values"][$i]." NOT NULL ";
                if(    $i < count($array["rows"])-1 ) $info = $info.",";
                        }
            $query = "CREATE TABLE ".$this->private_tables_name.$array["table"]." ";
            $query .= "( id INT NOT NULL AUTO_INCREMENT PRIMARY KEY, ".$info." )";
                        return     $query;   
                            }
                            }
                    }else return     "Error";
                        }
                }

    /* the use is simple */
    $database = new database(); // connection to database i used mysqli ...
    $array = array("table"=>"MRO", "rows"=>array("name","username") , "values" => array("VARCHAR (50) "," VARCHAR (50) ") );

    $query = array_create_table($array); // convert and create the query ...
    if($database->query($query)) echo "Work"; else echo "Error"; // result : work

    ?>
    jcwebb at dicoe dot com
    8 years ago
    When building apps, i like to see the whole statement when if fails.
    <?php
    $q    ="SELECT somecolumn FROM sometable"; //some instruction
    $r=mysqli_query($DBlink,$q) or die(mysqli_error($DBlink)." Q=".$q);
    ?>
    If theres an error (like my numerous typing mistakes) this shows the entire instruction.
    Good for development (not so good on production servers - simply find and replace when finished: $r=mysqli_query($DBlink,$q); )

    Hope it helps. Jon
    Beeners
    10 years ago
    Stored Procedures.

    Use mysqli_query to call a stored procedure that returns a result set.

    Here is a short example:

    <?php
    $mysqli     = new mysqli(DBURI,DBUSER,DBPASS,DBNAME);
    if (    mysqli_connect_errno())
    {
          printf("Connection failed: %s\n", mysqli_connect_error());
      exit();
    }

    $SQL = "CALL my_procedure($something)";
    if ( (    $result = $mysqli->query($SQL))===false )
    {
          printf("Invalid query: %s\nWhole query: %s\n", $mysqli->error, $SQL);
      exit();
    }

    while (    $myrow = $result->fetch_array(MYSQLI_ASSOC))
    {
          $aValue[]=$myrow["a"];
          $bValue[]=$myrow["b"];
    }
    $result->close();
    $mysqli->close();
    ?>
    I hope this saves someone some time.
    ceo at l-i-e dot com
    7 years ago
    Translation:
    "Couldn't fetch mysqli"

    You closed your connection and are trying to use it again.

    It has taken me DAYS to figure out what this obscure error message means...
    Igor
    7 years ago
    mysqli::query() can only execute one SQL statement.

    Use mysqli::multi_query() when you want to run multiple SQL statements within one query.
    joseph_robert_martinez at yahoo dot com
    2 years ago
    For those using with replication enabled on their servers,  add a mysqli_select_db() statement before any data modification queries.  MySQL replication does not handle statements with db.table the same and will not replicate to the slaves if a scheme is not selected before.

    Found out after days of resetting master and slaves on another site http://www.linuxquestions.org/questions/linux-server-73/mysql-5-1-not-replicating-properly-with-slave-823296/
    thomas dekker
    5 years ago
    Building inserts can be annoying. This helper function inserts an array into a table, using the key names as column names:

    <?php
          private function store_array (&$data, $table, $mysqli)
      {
            $cols = implode(',', array_keys($data));
        foreach (    array_values($data) as $value)
        {
          isset(    $vals) ? $vals .= ',' : $vals = '';
              $vals .= '\''.$this->mysql->real_escape_string($value).'\'';
        }
            $mysqli->real_query('INSERT INTO '.$table.' ('.$cols.') VALUES ('.$vals.')');
      }
    ?>

    Adapt it to your specific needs.
    marcus at synchromedia dot co dot uk
    4 years ago
    The exact type returned by a successful query is mysqli_result.
    andrey at php dot net
    10 years ago
    WARNING: This function was buggy on 64bit machines till 5.0.5. Affected versions 5.0.0-5.0.4. The problem appears when a value for the third parameter is passed - this will lead to instant FALSE returned by the function. Therefore if you need to use unbuffered query don't use this function with the aforementioned versions but you mysqli_real_query() and mysqli_use_result().
    If you have the rights to patch you PHP installation the fix is easy:
    In file ext/mysqli/myslqi_nonapi.c, function PHP_FUNCTION(mysqli_query)
    change
    unsigned int resultmode=0;
    to
    unsigned long resultmode=0;

    Thanks!
    blinki bill, argodak at yahoo dot com
    2 years ago
    Recently I had puzzling problem when performing DML queries, update in particular, each time a update query is called and then there are some more queries to follow this error will show on the page and go in the error_log:
    "Fatal error:  Exception thrown without a stack frame in Unknown on line 0"

    The strange thing is that all queries go through just fine so it didn't make much sense:

    $update = mysqli_query($connection, $query_string);
    if(!$update){
    echo 'Houston we have a problem '.mysqli_error($connection);
    exit;
    }

    In the above example "$update" is "true", mysqli_error() is empty and of course the update operation goes through, however the nasty super cryptic error appears on the page.
    What makes even less sense to me is how I fixed it - just called "mysqli_free_result" after the update query and the problem was gone, however because mysqli_free_result is not supposed to be called after DML queries (to free what, a boolean? lol) it needs to be wrapped in a try catch block:

    try{
    mysqli_free_result($update);
    }catch (Exception $e){
    //do nothing
    }

    So, I don't know why but it seems that when DML queries are responsible for:
    "Fatal error:  Exception thrown without a stack frame in Unknown on line 0"
    calling "mysqli_free_result" after the query seems to be fixing the issue
    info at ff dot net
    9 years ago
    Calling Stored Procedures

    Beeners' note/example will not work. Use mysqli_multi_query() to call a Stored Procedure. SP's have a second result-set which contains the status: 'OK' or 'ERR'. Using mysqli_query will not work, as there are multiple results.

    <?php
    $sQuery    ="CALL SomeSP('params')";
    if(!    mysqli_multi_query($sqlLink,$sQuery)) {
          // your error handler
    }
    $sqlResult=mysqli_store_result($sqlLink);

    if(    mysqli_more_results($this->sqlLink))//Catch 'OK'/'ERR'
          while(mysqli_next_result($this->sqlLink));
    ?>

    You will have to rewrite/expand this a bit for more usability of course, but it's just an example.
    antiriad at gmail dot com
    9 years ago
    this is a variant of mysqli_query that returns output parameters as a rowset.

    <?php
          function mysqli_exec($link, $command)
      {
              $select = '';
              $i2 = 0;
         
          while (    true)
          {
              $i1 = strpos($command, '@', $i2);
         
          if (    $i1 === false)
              break;
             
              $field = '';
              $i2 = $i1 + 1;
         
          while (    $i2 < strlen($command) &&
              (    $command[$i2] >= '0' && $command[$i2] <= '9') ||
              (    $command[$i2] >= 'A' && $command[$i2] <= 'Z') ||
              (    $command[$i2] >= 'a' && $command[$i2] <= 'z') ||
              (    $command[$i2] == '_'))
                  $i2++;
             
              $field = substr($command, $i1 + 1, $i2 - $i1 - 1);
             
          if (    strlen($select) == 0)
                $select = "select @{$field} as $field";
          else                   
                  $select = $select . ", @{$field} as $field";
          }
         
          if (    strlen($select) > 0)
          {     
                mysqli_query($link, $command);
            return     mysqli_query($link, $select);
          }
          else
            return     mysqli_query($link, $command);
      }
    ?>

    an example:

    <?php
      $link     = mysqli_connect('localhost', 'myusr', 'mypass') or die ('Error connecting to mysql: ' . mysqli_error($link));
          mysqli_select_db($link, 'clips');
     
          $user_name = 'test';
          $result = mysqli_exec($link, "call do_user_login('$user_name', @session_id, @msg)");
     
      while (    $row = mysqli_fetch_assoc($result))
      {
        echo     "session_id : {$row['session_id']} <br>";
        echo     "msg        : {$row['msg']} <br>";
      }
    ?>
    hunreal at gmail dot com
    11 years ago
    Use difference collation/character for connect, result.
    You can set the collation before your query.

    E.g. want to set the collation to utf8_general_ci
    you can send the query "SET NAMES 'utf8'" first

    <?php
    $mysqli    =new mysqli('localhost', 'root', 'password', 'test');
    $mysqli->query("SET NAMES 'utf8'");
    $q=$mysqli->query("select * from test");
    while(    $r=$q->fetch_assoc()) {
            print_r($r);
    }
    ?>

    There are many variables about character settings.
    By running sql command, SHOW VARIABLES LIKE 'char%';
    There are some variables control the character usage.

    character_set_client
    character_set_connection
    character_set_database
    character_set_results
    character_set_server
    character_set_system

    Also SET NAMES can repalce with one or some settings like SET character_set_results='utf8';
    popere dot noel at yahoo dot com
    2 years ago
    or you could just extend the class...
    in my case i already had a wraper for the db so something like this was easy :

    public function  free($result) {
     
      $result->free_result();
    $this->link->next_result();
    }

    just tried it and it works like a charm ;-)
    To Top