"""Tools for solving inequalities and systems of inequalities. """
from __future__ import print_function, division
from sympy.core import Symbol, Dummy, sympify
from sympy.core.compatibility import iterable
from sympy.core.exprtools import factor_terms
from sympy.core.relational import Relational, Eq, Ge, Lt, Ne
from sympy.sets import Interval
from sympy.sets.sets import FiniteSet, Union, EmptySet, Intersection
from sympy.sets.fancysets import ImageSet
from sympy.core.singleton import S
from sympy.core.function import expand_mul
from sympy.functions import Abs
from sympy.logic import And
from sympy.polys import Poly, PolynomialError, parallel_poly_from_expr
from sympy.polys.polyutils import _nsort
from sympy.utilities.iterables import sift
from sympy.utilities.misc import filldedent
[docs]def solve_poly_inequality(poly, rel):
"""Solve a polynomial inequality with rational coefficients.
Examples
========
>>> from sympy import Poly
>>> from sympy.abc import x
>>> from sympy.solvers.inequalities import solve_poly_inequality
>>> solve_poly_inequality(Poly(x, x, domain='ZZ'), '==')
[{0}]
>>> solve_poly_inequality(Poly(x**2 - 1, x, domain='ZZ'), '!=')
[Interval.open(-oo, -1), Interval.open(-1, 1), Interval.open(1, oo)]
>>> solve_poly_inequality(Poly(x**2 - 1, x, domain='ZZ'), '==')
[{-1}, {1}]
See Also
========
solve_poly_inequalities
"""
if not isinstance(poly, Poly):
raise ValueError(
'For efficiency reasons, `poly` should be a Poly instance')
if poly.is_number:
t = Relational(poly.as_expr(), 0, rel)
if t is S.true:
return [S.Reals]
elif t is S.false:
return [S.EmptySet]
else:
raise NotImplementedError(
"could not determine truth value of %s" % t)
reals, intervals = poly.real_roots(multiple=False), []
if rel == '==':
for root, _ in reals:
interval = Interval(root, root)
intervals.append(interval)
elif rel == '!=':
left = S.NegativeInfinity
for right, _ in reals + [(S.Infinity, 1)]:
interval = Interval(left, right, True, True)
intervals.append(interval)
left = right
else:
if poly.LC() > 0:
sign = +1
else:
sign = -1
eq_sign, equal = None, False
if rel == '>':
eq_sign = +1
elif rel == '<':
eq_sign = -1
elif rel == '>=':
eq_sign, equal = +1, True
elif rel == '<=':
eq_sign, equal = -1, True
else:
raise ValueError("'%s' is not a valid relation" % rel)
right, right_open = S.Infinity, True
for left, multiplicity in reversed(reals):
if multiplicity % 2:
if sign == eq_sign:
intervals.insert(
0, Interval(left, right, not equal, right_open))
sign, right, right_open = -sign, left, not equal
else:
if sign == eq_sign and not equal:
intervals.insert(
0, Interval(left, right, True, right_open))
right, right_open = left, True
elif sign != eq_sign and equal:
intervals.insert(0, Interval(left, left))
if sign == eq_sign:
intervals.insert(
0, Interval(S.NegativeInfinity, right, True, right_open))
return intervals
def solve_poly_inequalities(polys):
"""Solve polynomial inequalities with rational coefficients.
Examples
========
>>> from sympy.solvers.inequalities import solve_poly_inequalities
>>> from sympy.polys import Poly
>>> from sympy.abc import x
>>> solve_poly_inequalities(((
... Poly(x**2 - 3), ">"), (
... Poly(-x**2 + 1), ">")))
Union(Interval.open(-oo, -sqrt(3)), Interval.open(-1, 1), Interval.open(sqrt(3), oo))
"""
from sympy import Union
return Union(*[s for p in polys for s in solve_poly_inequality(*p)])
[docs]def solve_rational_inequalities(eqs):
"""Solve a system of rational inequalities with rational coefficients.
Examples
========
>>> from sympy.abc import x
>>> from sympy import Poly
>>> from sympy.solvers.inequalities import solve_rational_inequalities
>>> solve_rational_inequalities([[
... ((Poly(-x + 1), Poly(1, x)), '>='),
... ((Poly(-x + 1), Poly(1, x)), '<=')]])
{1}
>>> solve_rational_inequalities([[
... ((Poly(x), Poly(1, x)), '!='),
... ((Poly(-x + 1), Poly(1, x)), '>=')]])
Union(Interval.open(-oo, 0), Interval.Lopen(0, 1))
See Also
========
solve_poly_inequality
"""
result = S.EmptySet
for _eqs in eqs:
if not _eqs:
continue
global_intervals = [Interval(S.NegativeInfinity, S.Infinity)]
for (numer, denom), rel in _eqs:
numer_intervals = solve_poly_inequality(numer*denom, rel)
denom_intervals = solve_poly_inequality(denom, '==')
intervals = []
for numer_interval in numer_intervals:
for global_interval in global_intervals:
interval = numer_interval.intersect(global_interval)
if interval is not S.EmptySet:
intervals.append(interval)
global_intervals = intervals
intervals = []
for global_interval in global_intervals:
for denom_interval in denom_intervals:
global_interval -= denom_interval
if global_interval is not S.EmptySet:
intervals.append(global_interval)
global_intervals = intervals
if not global_intervals:
break
for interval in global_intervals:
result = result.union(interval)
return result
[docs]def reduce_rational_inequalities(exprs, gen, relational=True):
"""Reduce a system of rational inequalities with rational coefficients.
Examples
========
>>> from sympy import Poly, Symbol
>>> from sympy.solvers.inequalities import reduce_rational_inequalities
>>> x = Symbol('x', real=True)
>>> reduce_rational_inequalities([[x**2 <= 0]], x)
Eq(x, 0)
>>> reduce_rational_inequalities([[x + 2 > 0]], x)
(-2 < x) & (x < oo)
>>> reduce_rational_inequalities([[(x + 2, ">")]], x)
(-2 < x) & (x < oo)
>>> reduce_rational_inequalities([[x + 2]], x)
Eq(x, -2)
"""
exact = True
eqs = []
solution = S.Reals if exprs else S.EmptySet
for _exprs in exprs:
_eqs = []
for expr in _exprs:
if isinstance(expr, tuple):
expr, rel = expr
else:
if expr.is_Relational:
expr, rel = expr.lhs - expr.rhs, expr.rel_op
else:
expr, rel = expr, '=='
if expr is S.true:
numer, denom, rel = S.Zero, S.One, '=='
elif expr is S.false:
numer, denom, rel = S.One, S.One, '=='
else:
numer, denom = expr.together().as_numer_denom()
try:
(numer, denom), opt = parallel_poly_from_expr(
(numer, denom), gen)
except PolynomialError:
raise PolynomialError(filldedent('''
only polynomials and rational functions are
supported in this context.
'''))
if not opt.domain.is_Exact:
numer, denom, exact = numer.to_exact(), denom.to_exact(), False
domain = opt.domain.get_exact()
if not (domain.is_ZZ or domain.is_QQ):
expr = numer/denom
expr = Relational(expr, 0, rel)
solution &= solve_univariate_inequality(expr, gen, relational=False)
else:
_eqs.append(((numer, denom), rel))
if _eqs:
eqs.append(_eqs)
if eqs:
solution &= solve_rational_inequalities(eqs)
exclude = solve_rational_inequalities([[((d, d.one), '==')
for i in eqs for ((n, d), _) in i if d.has(gen)]])
solution -= exclude
if not exact and solution:
solution = solution.evalf()
if relational:
solution = solution.as_relational(gen)
return solution
[docs]def reduce_abs_inequality(expr, rel, gen):
"""Reduce an inequality with nested absolute values.
Examples
========
>>> from sympy import Abs, Symbol
>>> from sympy.solvers.inequalities import reduce_abs_inequality
>>> x = Symbol('x', real=True)
>>> reduce_abs_inequality(Abs(x - 5) - 3, '<', x)
(2 < x) & (x < 8)
>>> reduce_abs_inequality(Abs(x + 2)*3 - 13, '<', x)
(-19/3 < x) & (x < 7/3)
See Also
========
reduce_abs_inequalities
"""
if gen.is_real is False:
raise TypeError(filldedent('''
can't solve inequalities with absolute values containing
non-real variables.
'''))
def _bottom_up_scan(expr):
exprs = []
if expr.is_Add or expr.is_Mul:
op = expr.func
for arg in expr.args:
_exprs = _bottom_up_scan(arg)
if not exprs:
exprs = _exprs
else:
args = []
for expr, conds in exprs:
for _expr, _conds in _exprs:
args.append((op(expr, _expr), conds + _conds))
exprs = args
elif expr.is_Pow:
n = expr.exp
if not n.is_Integer:
raise ValueError("Only Integer Powers are allowed on Abs.")
_exprs = _bottom_up_scan(expr.base)
for expr, conds in _exprs:
exprs.append((expr**n, conds))
elif isinstance(expr, Abs):
_exprs = _bottom_up_scan(expr.args[0])
for expr, conds in _exprs:
exprs.append(( expr, conds + [Ge(expr, 0)]))
exprs.append((-expr, conds + [Lt(expr, 0)]))
else:
exprs = [(expr, [])]
return exprs
exprs = _bottom_up_scan(expr)
mapping = {'<': '>', '<=': '>='}
inequalities = []
for expr, conds in exprs:
if rel not in mapping.keys():
expr = Relational( expr, 0, rel)
else:
expr = Relational(-expr, 0, mapping[rel])
inequalities.append([expr] + conds)
return reduce_rational_inequalities(inequalities, gen)
[docs]def reduce_abs_inequalities(exprs, gen):
"""Reduce a system of inequalities with nested absolute values.
Examples
========
>>> from sympy import Abs, Symbol
>>> from sympy.abc import x
>>> from sympy.solvers.inequalities import reduce_abs_inequalities
>>> x = Symbol('x', real=True)
>>> reduce_abs_inequalities([(Abs(3*x - 5) - 7, '<'),
... (Abs(x + 25) - 13, '>')], x)
(-2/3 < x) & (x < 4) & (((-oo < x) & (x < -38)) | ((-12 < x) & (x < oo)))
>>> reduce_abs_inequalities([(Abs(x - 4) + Abs(3*x - 5) - 7, '<')], x)
(1/2 < x) & (x < 4)
See Also
========
reduce_abs_inequality
"""
return And(*[ reduce_abs_inequality(expr, rel, gen)
for expr, rel in exprs ])
[docs]def solve_univariate_inequality(expr, gen, relational=True, domain=S.Reals, continuous=False):
"""Solves a real univariate inequality.
Parameters
==========
expr : Relational
The target inequality
gen : Symbol
The variable for which the inequality is solved
relational : bool
A Relational type output is expected or not
domain : Set
The domain over which the equation is solved
continuous: bool
True if expr is known to be continuous over the given domain
(and so continuous_domain() doesn't need to be called on it)
Raises
======
NotImplementedError
The solution of the inequality cannot be determined due to limitation
in `solvify`.
Notes
=====
Currently, we cannot solve all the inequalities due to limitations in
`solvify`. Also, the solution returned for trigonometric inequalities
are restricted in its periodic interval.
See Also
========
solvify: solver returning solveset solutions with solve's output API
Examples
========
>>> from sympy.solvers.inequalities import solve_univariate_inequality
>>> from sympy import Symbol, sin, Interval, S
>>> x = Symbol('x')
>>> solve_univariate_inequality(x**2 >= 4, x)
((2 <= x) & (x < oo)) | ((x <= -2) & (-oo < x))
>>> solve_univariate_inequality(x**2 >= 4, x, relational=False)
Union(Interval(-oo, -2), Interval(2, oo))
>>> domain = Interval(0, S.Infinity)
>>> solve_univariate_inequality(x**2 >= 4, x, False, domain)
Interval(2, oo)
>>> solve_univariate_inequality(sin(x) > 0, x, relational=False)
Interval.open(0, pi)
"""
from sympy import im
from sympy.calculus.util import (continuous_domain, periodicity,
function_range)
from sympy.solvers.solvers import denoms
from sympy.solvers.solveset import solveset_real, solvify, solveset
from sympy.solvers.solvers import solve
# This keeps the function independent of the assumptions about `gen`.
# `solveset` makes sure this function is called only when the domain is
# real.
_gen = gen
_domain = domain
if gen.is_real is False:
rv = S.EmptySet
return rv if not relational else rv.as_relational(_gen)
elif gen.is_real is None:
gen = Dummy('gen', real=True)
try:
expr = expr.xreplace({_gen: gen})
except TypeError:
raise TypeError(filldedent('''
When gen is real, the relational has a complex part
which leads to an invalid comparison like I < 0.
'''))
rv = None
if expr is S.true:
rv = domain
elif expr is S.false:
rv = S.EmptySet
else:
e = expr.lhs - expr.rhs
period = periodicity(e, gen)
if period is S.Zero:
e = expand_mul(e)
const = expr.func(e, 0)
if const is S.true:
rv = domain
elif const is S.false:
rv = S.EmptySet
elif period is not None:
frange = function_range(e, gen, domain)
rel = expr.rel_op
if rel == '<' or rel == '<=':
if expr.func(frange.sup, 0):
rv = domain
elif not expr.func(frange.inf, 0):
rv = S.EmptySet
elif rel == '>' or rel == '>=':
if expr.func(frange.inf, 0):
rv = domain
elif not expr.func(frange.sup, 0):
rv = S.EmptySet
inf, sup = domain.inf, domain.sup
if sup - inf is S.Infinity:
domain = Interval(0, period, False, True)
if rv is None:
n, d = e.as_numer_denom()
try:
if gen not in n.free_symbols and len(e.free_symbols) > 1:
raise ValueError
# this might raise ValueError on its own
# or it might give None...
solns = solvify(e, gen, domain)
if solns is None:
# in which case we raise ValueError
raise ValueError
except (ValueError, NotImplementedError):
# replace gen with generic x since it's
# univariate anyway
raise NotImplementedError(filldedent('''
The inequality, %s, cannot be solved using
solve_univariate_inequality.
''' % expr.subs(gen, Symbol('x'))))
expanded_e = expand_mul(e)
def valid(x):
# this is used to see if gen=x satisfies the
# relational by substituting it into the
# expanded form and testing against 0, e.g.
# if expr = x*(x + 1) < 2 then e = x*(x + 1) - 2
# and expanded_e = x**2 + x - 2; the test is
# whether a given value of x satisfies
# x**2 + x - 2 < 0
#
# expanded_e, expr and gen used from enclosing scope
v = expanded_e.subs(gen, expand_mul(x))
try:
r = expr.func(v, 0)
except TypeError:
r = S.false
if r in (S.true, S.false):
return r
if v.is_real is False:
return S.false
else:
v = v.n(2)
if v.is_comparable:
return expr.func(v, 0)
# not comparable or couldn't be evaluated
raise NotImplementedError(
'relationship did not evaluate: %s' % r)
singularities = []
for d in denoms(expr, gen):
singularities.extend(solvify(d, gen, domain))
if not continuous:
domain = continuous_domain(expanded_e, gen, domain)
include_x = '=' in expr.rel_op and expr.rel_op != '!='
try:
discontinuities = set(domain.boundary -
FiniteSet(domain.inf, domain.sup))
# remove points that are not between inf and sup of domain
critical_points = FiniteSet(*(solns + singularities + list(
discontinuities))).intersection(
Interval(domain.inf, domain.sup,
domain.inf not in domain, domain.sup not in domain))
if all(r.is_number for r in critical_points):
reals = _nsort(critical_points, separated=True)[0]
else:
sifted = sift(critical_points, lambda x: x.is_real)
if sifted[None]:
# there were some roots that weren't known
# to be real
raise NotImplementedError
try:
reals = sifted[True]
if len(reals) > 1:
reals = list(sorted(reals))
except TypeError:
raise NotImplementedError
except NotImplementedError:
raise NotImplementedError('sorting of these roots is not supported')
# If expr contains imaginary coefficients, only take real
# values of x for which the imaginary part is 0
make_real = S.Reals
if im(expanded_e) != S.Zero:
check = True
im_sol = FiniteSet()
try:
a = solveset(im(expanded_e), gen, domain)
if not isinstance(a, Interval):
for z in a:
if z not in singularities and valid(z) and z.is_real:
im_sol += FiniteSet(z)
else:
start, end = a.inf, a.sup
for z in _nsort(critical_points + FiniteSet(end)):
valid_start = valid(start)
if start != end:
valid_z = valid(z)
pt = _pt(start, z)
if pt not in singularities and pt.is_real and valid(pt):
if valid_start and valid_z:
im_sol += Interval(start, z)
elif valid_start:
im_sol += Interval.Ropen(start, z)
elif valid_z:
im_sol += Interval.Lopen(start, z)
else:
im_sol += Interval.open(start, z)
start = z
for s in singularities:
im_sol -= FiniteSet(s)
except (TypeError):
im_sol = S.Reals
check = False
if isinstance(im_sol, EmptySet):
raise ValueError(filldedent('''
%s contains imaginary parts which cannot be
made 0 for any value of %s satisfying the
inequality, leading to relations like I < 0.
''' % (expr.subs(gen, _gen), _gen)))
make_real = make_real.intersect(im_sol)
empty = sol_sets = [S.EmptySet]
start = domain.inf
if valid(start) and start.is_finite:
sol_sets.append(FiniteSet(start))
for x in reals:
end = x
if valid(_pt(start, end)):
sol_sets.append(Interval(start, end, True, True))
if x in singularities:
singularities.remove(x)
else:
if x in discontinuities:
discontinuities.remove(x)
_valid = valid(x)
else: # it's a solution
_valid = include_x
if _valid:
sol_sets.append(FiniteSet(x))
start = end
end = domain.sup
if valid(end) and end.is_finite:
sol_sets.append(FiniteSet(end))
if valid(_pt(start, end)):
sol_sets.append(Interval.open(start, end))
if im(expanded_e) != S.Zero and check:
rv = (make_real).intersect(_domain)
else:
rv = Intersection(
(Union(*sol_sets)), make_real, _domain).subs(gen, _gen)
return rv if not relational else rv.as_relational(_gen)
def _pt(start, end):
"""Return a point between start and end"""
if not start.is_infinite and not end.is_infinite:
pt = (start + end)/2
elif start.is_infinite and end.is_infinite:
pt = S.Zero
else:
if (start.is_infinite and start.is_positive is None or
end.is_infinite and end.is_positive is None):
raise ValueError('cannot proceed with unsigned infinite values')
if (end.is_infinite and end.is_negative or
start.is_infinite and start.is_positive):
start, end = end, start
# if possible, use a multiple of self which has
# better behavior when checking assumptions than
# an expression obtained by adding or subtracting 1
if end.is_infinite:
if start.is_positive:
pt = start*2
elif start.is_negative:
pt = start*S.Half
else:
pt = start + 1
elif start.is_infinite:
if end.is_positive:
pt = end*S.Half
elif end.is_negative:
pt = end*2
else:
pt = end - 1
return pt
def _solve_inequality(ie, s, linear=False):
"""Return the inequality with s isolated on the left, if possible.
If the relationship is non-linear, a solution involving And or Or
may be returned. False or True are returned if the relationship
is never True or always True, respectively.
If `linear` is True (default is False) an `s`-dependent expression
will be isolated on the left, if possible
but it will not be solved for `s` unless the expression is linear
in `s`. Furthermore, only "safe" operations which don't change the
sense of the relationship are applied: no division by an unsigned
value is attempted unless the relationship involves Eq or Ne and
no division by a value not known to be nonzero is ever attempted.
Examples
========
>>> from sympy import Eq, Symbol
>>> from sympy.solvers.inequalities import _solve_inequality as f
>>> from sympy.abc import x, y
For linear expressions, the symbol can be isolated:
>>> f(x - 2 < 0, x)
x < 2
>>> f(-x - 6 < x, x)
x > -3
Sometimes nonlinear relationships will be False
>>> f(x**2 + 4 < 0, x)
False
Or they may involve more than one region of values:
>>> f(x**2 - 4 < 0, x)
(-2 < x) & (x < 2)
To restrict the solution to a relational, set linear=True
and only the x-dependent portion will be isolated on the left:
>>> f(x**2 - 4 < 0, x, linear=True)
x**2 < 4
Division of only nonzero quantities is allowed, so x cannot
be isolated by dividing by y:
>>> y.is_nonzero is None # it is unknown whether it is 0 or not
True
>>> f(x*y < 1, x)
x*y < 1
And while an equality (or inequality) still holds after dividing by a
non-zero quantity
>>> nz = Symbol('nz', nonzero=True)
>>> f(Eq(x*nz, 1), x)
Eq(x, 1/nz)
the sign must be known for other inequalities involving > or <:
>>> f(x*nz <= 1, x)
nz*x <= 1
>>> p = Symbol('p', positive=True)
>>> f(x*p <= 1, x)
x <= 1/p
When there are denominators in the original expression that
are removed by expansion, conditions for them will be returned
as part of the result:
>>> f(x < x*(2/x - 1), x)
(x < 1) & Ne(x, 0)
"""
from sympy.solvers.solvers import denoms
if s not in ie.free_symbols:
return ie
if ie.rhs == s:
ie = ie.reversed
if ie.lhs == s and s not in ie.rhs.free_symbols:
return ie
def classify(ie, s, i):
# return True or False if ie evaluates when substituting s with
# i else None (if unevaluated) or NaN (when there is an error
# in evaluating)
try:
v = ie.subs(s, i)
if v is S.NaN:
return v
elif v not in (True, False):
return
return v
except TypeError:
return S.NaN
rv = None
oo = S.Infinity
expr = ie.lhs - ie.rhs
try:
p = Poly(expr, s)
if p.degree() == 0:
rv = ie.func(p.as_expr(), 0)
elif not linear and p.degree() > 1:
# handle in except clause
raise NotImplementedError
except (PolynomialError, NotImplementedError):
if not linear:
try:
rv = reduce_rational_inequalities([[ie]], s)
except PolynomialError:
rv = solve_univariate_inequality(ie, s)
# remove restrictions wrt +/-oo that may have been
# applied when using sets to simplify the relationship
okoo = classify(ie, s, oo)
if okoo is S.true and classify(rv, s, oo) is S.false:
rv = rv.subs(s < oo, True)
oknoo = classify(ie, s, -oo)
if (oknoo is S.true and
classify(rv, s, -oo) is S.false):
rv = rv.subs(-oo < s, True)
rv = rv.subs(s > -oo, True)
if rv is S.true:
rv = (s <= oo) if okoo is S.true else (s < oo)
if oknoo is not S.true:
rv = And(-oo < s, rv)
else:
p = Poly(expr)
conds = []
if rv is None:
e = p.as_expr() # this is in expanded form
# Do a safe inversion of e, moving non-s terms
# to the rhs and dividing by a nonzero factor if
# the relational is Eq/Ne; for other relationals
# the sign must also be positive or negative
rhs = 0
b, ax = e.as_independent(s, as_Add=True)
e -= b
rhs -= b
ef = factor_terms(e)
a, e = ef.as_independent(s, as_Add=False)
if (a.is_zero != False or # don't divide by potential 0
a.is_negative ==
a.is_positive is None and # if sign is not known then
ie.rel_op not in ('!=', '==')): # reject if not Eq/Ne
e = ef
a = S.One
rhs /= a
if a.is_positive:
rv = ie.func(e, rhs)
else:
rv = ie.reversed.func(e, rhs)
# return conditions under which the value is
# valid, too.
beginning_denoms = denoms(ie.lhs) | denoms(ie.rhs)
current_denoms = denoms(rv)
for d in beginning_denoms - current_denoms:
c = _solve_inequality(Eq(d, 0), s, linear=linear)
if isinstance(c, Eq) and c.lhs == s:
if classify(rv, s, c.rhs) is S.true:
# rv is permitting this value but it shouldn't
conds.append(~c)
for i in (-oo, oo):
if (classify(rv, s, i) is S.true and
classify(ie, s, i) is not S.true):
conds.append(s < i if i is oo else i < s)
conds.append(rv)
return And(*conds)
def _reduce_inequalities(inequalities, symbols):
# helper for reduce_inequalities
poly_part, abs_part = {}, {}
other = []
for inequality in inequalities:
expr, rel = inequality.lhs, inequality.rel_op # rhs is 0
# check for gens using atoms which is more strict than free_symbols to
# guard against EX domain which won't be handled by
# reduce_rational_inequalities
gens = expr.atoms(Symbol)
if len(gens) == 1:
gen = gens.pop()
else:
common = expr.free_symbols & symbols
if len(common) == 1:
gen = common.pop()
other.append(_solve_inequality(Relational(expr, 0, rel), gen))
continue
else:
raise NotImplementedError(filldedent('''
inequality has more than one symbol of interest.
'''))
if expr.is_polynomial(gen):
poly_part.setdefault(gen, []).append((expr, rel))
else:
components = expr.find(lambda u:
u.has(gen) and (
u.is_Function or u.is_Pow and not u.exp.is_Integer))
if components and all(isinstance(i, Abs) for i in components):
abs_part.setdefault(gen, []).append((expr, rel))
else:
other.append(_solve_inequality(Relational(expr, 0, rel), gen))
poly_reduced = []
abs_reduced = []
for gen, exprs in poly_part.items():
poly_reduced.append(reduce_rational_inequalities([exprs], gen))
for gen, exprs in abs_part.items():
abs_reduced.append(reduce_abs_inequalities(exprs, gen))
return And(*(poly_reduced + abs_reduced + other))
[docs]def reduce_inequalities(inequalities, symbols=[]):
"""Reduce a system of inequalities with rational coefficients.
Examples
========
>>> from sympy import sympify as S, Symbol
>>> from sympy.abc import x, y
>>> from sympy.solvers.inequalities import reduce_inequalities
>>> reduce_inequalities(0 <= x + 3, [])
(-3 <= x) & (x < oo)
>>> reduce_inequalities(0 <= x + y*2 - 1, [x])
(x < oo) & (x >= 1 - 2*y)
"""
if not iterable(inequalities):
inequalities = [inequalities]
inequalities = [sympify(i) for i in inequalities]
gens = set().union(*[i.free_symbols for i in inequalities])
if not iterable(symbols):
symbols = [symbols]
symbols = (set(symbols) or gens) & gens
if any(i.is_real is False for i in symbols):
raise TypeError(filldedent('''
inequalities cannot contain symbols that are not real.
'''))
# make vanilla symbol real
recast = {i: Dummy(i.name, real=True)
for i in gens if i.is_real is None}
inequalities = [i.xreplace(recast) for i in inequalities]
symbols = {i.xreplace(recast) for i in symbols}
# prefilter
keep = []
for i in inequalities:
if isinstance(i, Relational):
i = i.func(i.lhs.as_expr() - i.rhs.as_expr(), 0)
elif i not in (True, False):
i = Eq(i, 0)
if i == True:
continue
elif i == False:
return S.false
if i.lhs.is_number:
raise NotImplementedError(
"could not determine truth value of %s" % i)
keep.append(i)
inequalities = keep
del keep
# solve system
rv = _reduce_inequalities(inequalities, symbols)
# restore original symbols and return
return rv.xreplace({v: k for k, v in recast.items()})
