Aliases:
tf.accumulate_ntf.math.accumulate_n
tf.math.accumulate_n(
inputs,
shape=None,
tensor_dtype=None,
name=None
)
Defined in tensorflow/python/ops/math_ops.py.
Returns the element-wise sum of a list of tensors.
Optionally, pass shape and tensor_dtype for shape and type checking,
otherwise, these are inferred.
tf.math.accumulate_n performs the same operation as tf.add_n, but does not
wait for all of its inputs to be ready before beginning to sum. This can
save memory if inputs are ready at different times, since minimum temporary
storage is proportional to the output size rather than the inputs size.
accumulate_n is differentiable (but wasn't previous to TensorFlow 1.7).
For example:
a = tf.constant([[1, 2], [3, 4]])
b = tf.constant([[5, 0], [0, 6]])
tf.math.accumulate_n([a, b, a]) # [[7, 4], [6, 14]]
# Explicitly pass shape and type
tf.math.accumulate_n([a, b, a], shape=[2, 2], tensor_dtype=tf.int32)
# [[7, 4],
# [6, 14]]
Args:
inputs: A list ofTensorobjects, each with same shape and type.shape: Shape of elements ofinputs.tensor_dtype: The type ofinputs.name: A name for the operation (optional).
Returns:
A Tensor of same shape and type as the elements of inputs.
Raises:
ValueError: Ifinputsdon't all have same shape and dtype or the shape cannot be inferred.