Aliases:
tf.accumulate_n
tf.math.accumulate_n
tf.math.accumulate_n(
inputs,
shape=None,
tensor_dtype=None,
name=None
)
Defined in tensorflow/python/ops/math_ops.py
.
Returns the element-wise sum of a list of tensors.
Optionally, pass shape
and tensor_dtype
for shape and type checking,
otherwise, these are inferred.
tf.math.accumulate_n
performs the same operation as tf.add_n
, but does not
wait for all of its inputs to be ready before beginning to sum. This can
save memory if inputs are ready at different times, since minimum temporary
storage is proportional to the output size rather than the inputs size.
accumulate_n
is differentiable (but wasn't previous to TensorFlow 1.7).
For example:
a = tf.constant([[1, 2], [3, 4]])
b = tf.constant([[5, 0], [0, 6]])
tf.math.accumulate_n([a, b, a]) # [[7, 4], [6, 14]]
# Explicitly pass shape and type
tf.math.accumulate_n([a, b, a], shape=[2, 2], tensor_dtype=tf.int32)
# [[7, 4],
# [6, 14]]
Args:
inputs
: A list ofTensor
objects, each with same shape and type.shape
: Shape of elements ofinputs
.tensor_dtype
: The type ofinputs
.name
: A name for the operation (optional).
Returns:
A Tensor
of same shape and type as the elements of inputs
.
Raises:
ValueError
: Ifinputs
don't all have same shape and dtype or the shape cannot be inferred.