tf.sparse_to_dense(
sparse_indices,
output_shape,
sparse_values,
default_value=0,
validate_indices=True,
name=None
)
Defined in tensorflow/python/ops/sparse_ops.py.
Converts a sparse representation into a dense tensor. (deprecated)
Builds an array dense with shape output_shape such that
# If sparse_indices is scalar
dense[i] = (i == sparse_indices ? sparse_values : default_value)
# If sparse_indices is a vector, then for each i
dense[sparse_indices[i]] = sparse_values[i]
# If sparse_indices is an n by d matrix, then for each i in [0, n)
dense[sparse_indices[i][0], ..., sparse_indices[i][d-1]] = sparse_values[i]
All other values in dense are set to default_value. If sparse_values
is a scalar, all sparse indices are set to this single value.
Indices should be sorted in lexicographic order, and indices must not
contain any repeats. If validate_indices is True, these properties
are checked during execution.
Args:
sparse_indices: A 0-D, 1-D, or 2-DTensorof typeint32orint64.sparse_indices[i]contains the complete index wheresparse_values[i]will be placed.output_shape: A 1-DTensorof the same type assparse_indices. Shape of the dense output tensor.sparse_values: A 0-D or 1-DTensor. Values corresponding to each row ofsparse_indices, or a scalar value to be used for all sparse indices.default_value: A 0-DTensorof the same type assparse_values. Value to set for indices not specified insparse_indices. Defaults to zero.validate_indices: A boolean value. If True, indices are checked to make sure they are sorted in lexicographic order and that there are no repeats.name: A name for the operation (optional).
Returns:
Dense Tensor of shape output_shape. Has the same type as
sparse_values.