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Normalizes along dimension axis using an L2 norm. (deprecated arguments)
tf.compat.v1.linalg.l2_normalize(
x, axis=None, epsilon=1e-12, name=None, dim=None
)
Warning: SOME ARGUMENTS ARE DEPRECATED: (dim). They will be removed in a future version.
Instructions for updating:
dim is deprecated, use axis instead
For a 1-D tensor with axis = 0, computes
output = x / sqrt(max(sum(x**2), epsilon))
For x with more dimensions, independently normalizes each 1-D slice along
dimension axis.
x: A Tensor.axis: Dimension along which to normalize. A scalar or a vector of
integers.epsilon: A lower bound value for the norm. Will use sqrt(epsilon) as the
divisor if norm < sqrt(epsilon).name: A name for this operation (optional).dim: Deprecated alias for axis.A Tensor with the same shape as x.