View source on GitHub |
Normalizes along dimension axis
using an L2 norm.
tf.math.l2_normalize(
x, axis=None, epsilon=1e-12, name=None
)
For a 1-D tensor with axis = 0
, computes
output = x / sqrt(max(sum(x**2), epsilon))
For x
with more dimensions, independently normalizes each 1-D slice along
dimension axis
.
x
: A Tensor
.axis
: Dimension along which to normalize. A scalar or a vector of
integers.epsilon
: A lower bound value for the norm. Will use sqrt(epsilon)
as the
divisor if norm < sqrt(epsilon)
.name
: A name for this operation (optional).A Tensor
with the same shape as x
.