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Normalizes along dimension axis using an L2 norm.
tf.math.l2_normalize(
    x, axis=None, epsilon=1e-12, name=None
)
For a 1-D tensor with axis = 0, computes
output = x / sqrt(max(sum(x**2), epsilon))
For x with more dimensions, independently normalizes each 1-D slice along
dimension axis.
x: A Tensor.axis: Dimension along which to normalize.  A scalar or a vector of
integers.epsilon: A lower bound value for the norm. Will use sqrt(epsilon) as the
divisor if norm < sqrt(epsilon).name: A name for this operation (optional).A Tensor with the same shape as x.