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Tensor contraction of a and b along specified axes and outer product.
tf.tensordot(
a, b, axes, name=None
)
Tensordot (also known as tensor contraction) sums the product of elements
from a
and b
over the indices specified by a_axes
and b_axes
.
The lists a_axes
and b_axes
specify those pairs of axes along which to
contract the tensors. The axis a_axes[i]
of a
must have the same dimension
as axis b_axes[i]
of b
for all i
in range(0, len(a_axes))
. The lists
a_axes
and b_axes
must have identical length and consist of unique
integers that specify valid axes for each of the tensors. Additionally
outer product is supported by passing axes=0
.
This operation corresponds to numpy.tensordot(a, b, axes)
.
Example 1: When a
and b
are matrices (order 2), the case axes = 1
is equivalent to matrix multiplication.
Example 2: When a
and b
are matrices (order 2), the case
axes = [[1], [0]]
is equivalent to matrix multiplication.
Example 3: When a
and b
are matrices (order 2), the case axes=0
gives
the outer product, a tensor of order 4.
Example 4: Suppose that \(a_{ijk}\) and \(b_{lmn}\) represent two
tensors of order 3. Then, contract(a, b, [[0], [2]])
is the order 4 tensor
\(c_{jklm}\) whose entry
corresponding to the indices \((j,k,l,m)\) is given by:
\( c_{jklm} = \sum_i a_{ijk} b_{lmi} \).
In general, order(c) = order(a) + order(b) - 2*len(axes[0])
.
a
: Tensor
of type float32
or float64
.b
: Tensor
with the same type as a
.axes
: Either a scalar N
, or a list or an int32
Tensor
of shape [2, k].
If axes is a scalar, sum over the last N axes of a and the first N axes of
b in order. If axes is a list or Tensor
the first and second row contain
the set of unique integers specifying axes along which the contraction is
computed, for a
and b
, respectively. The number of axes for a
and
b
must be equal. If axes=0
, computes the outer product between a
and
b
.name
: A name for the operation (optional).A Tensor
with the same type as a
.
ValueError
: If the shapes of a
, b
, and axes
are incompatible.IndexError
: If the values in axes exceed the rank of the corresponding
tensor.