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Method

Returns a portion of a string. The first character is numbered 1.

Syntax

result=MidB(source, start [,length])
OR
result=stringVariable.MidB(start [,length])

Part	Type	Description
result	String	The portion of source from start and continuing for length characters or all remaining characters if length is not specified. The encoding of result is the same as the source.
source	String	Required. The string from which bytes are returned.
start	Integer	Required. The position of the first byte to be returned. If start is greater than the number of bytes in source, an empty string is returned.
length	Integer	Optional. The number of bytes to return from source. If omitted, all bytes from start to the end of source are returned. If length + start is greater than the length of source, all bytes from start to the end of source will be returned.
stringVariable	String	Any variable of type String.

Notes

MidB treats source as a series of bytes, rather than a series of characters. MidB should be used when source represents binary data. The encoding of the result is the same as the encoding of the source string.

If you need to extract characters rather than bytes, use the Mid function. To determine the number of bytes in a string, use the LenB function.

Examples

These examples use the MidB function to return portions of a string.

Dim s As String
s = MidB("This is a test", 6) // returns "is a test"
s = MidB("This is a test", 11, 4) // returns "test"

s = "This is a test"
s = s.MidB(11, 4) // returns "test"

See Also

AscB, ChrB, InStrB, LeftB, LenB, Mid, RightB functions.