Javax.Xml.Parsers.SAXParser.Parse Method
Parse the content described by the giving Uniform Resource Identifier (URI) as XML using the specified Org.Xml.Sax.Helpers.DefaultHandler.

Syntax

[Android.Runtime.Register("parse", "(Ljava/lang/String;Lorg/xml/sax/helpers/DefaultHandler;)V", "GetParse_Ljava_lang_String_Lorg_xml_sax_helpers_DefaultHandler_Handler")]
public virtual void Parse (string uri, Org.Xml.Sax.Helpers.DefaultHandler handler)

See Also

Org.Xml.Sax.IDocumentHandler

Parameters

uri
The location of the content to be parsed.
dh
The SAX DefaultHandler to use.

Exceptions

TypeReason
Java.Lang.IllegalArgumentExceptionIf the uri is null.
Java.IO.IOExceptionIf any IO errors occur.
Org.Xml.Sax.SAXExceptionIf any SAX errors occur during processing.

Remarks

Parse the content described by the giving Uniform Resource Identifier (URI) as XML using the specified Org.Xml.Sax.Helpers.DefaultHandler.

[Android Documentation]

Requirements

Namespace: Javax.Xml.Parsers
Assembly: Mono.Android (in Mono.Android.dll)
Assembly Versions: 0.0.0.0
Since: Added in API level 1