std::multiset::erase
From cppreference.com
(1) | ||
void erase( iterator pos );
|
(until C++11) | |
iterator erase( const_iterator pos );
|
(since C++11) | |
iterator erase( iterator pos );
|
(since C++17) | |
(2) | ||
void erase( iterator first, iterator last );
|
(until C++11) | |
iterator erase( const_iterator first, const_iterator last );
|
(since C++11) | |
size_type erase( const key_type& key );
|
(3) | |
Removes specified elements from the container.
1) Removes the element at
pos
.
2) Removes the elements in the range
[first; last)
, which must be a valid range in *this.
3) Removes all elements with the key equivalent to
key
.References and iterators to the erased elements are invalidated. Other references and iterators are not affected.
The iterator pos
must be valid and dereferenceable. Thus the end() iterator (which is valid, but is not dereferencable) cannot be used as a value for pos
.
Contents |
[edit] Parameters
pos | - | iterator to the element to remove |
first, last | - | range of elements to remove |
key | - | key value of the elements to remove |
[edit] Return value
1-2) Iterator following the last removed element.
3) Number of elements removed.
[edit] Exceptions
1,2) (none)
3) Any exceptions thrown by the
Compare
object.[edit] Complexity
Given an instance c
of multiset
:
1) Amortized constant
2) log(c.size()) + std::distance(first, last)
3) log(c.size()) + c.count(k)
[edit] Example
Run this code
#include <set> #include <iostream> int main() { std::multiset<int> c = {1, 2, 3, 4, 5, 6, 7, 8, 9}; // erase all odd numbers from c for(auto it = c.begin(); it != c.end(); ) if(*it % 2 == 1) it = c.erase(it); else ++it; for(int n : c) std::cout << n << ' '; }
Output:
2 4 6 8
[edit] See also
clears the contents (public member function) |