std::log2
From cppreference.com
Defined in header
<cmath>
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float log2( float arg );
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(1) | (since C++11) |
double log2( double arg );
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(2) | (since C++11) |
long double log2( long double arg );
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(3) | (since C++11) |
double log2( Integral arg );
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(4) | (since C++11) |
1-3) Computes the binary (base-2) logarithm of arg.
4) A set of overloads or a function template accepting an argument of any integral type. Equivalent to 2) (the argument is cast to double).
Contents |
[edit] Parameters
arg | - | value of floating-point or Integral type |
[edit] Return value
If no errors occur, the base-2 logarithm of arg
(log
2(arg) or lb(arg)) is returned.
If a domain error occurs, an implementation-defined value is returned (NaN where supported)
If a pole error occurs, -HUGE_VAL
, -HUGE_VALF
, or -HUGE_VALL
is returned.
[edit] Error handling
Errors are reported as specified in math_errhandling
Domain error occurs if arg
is less than zero.
Pole error may occur if arg
is zero.
If the implementation supports IEEE floating-point arithmetic (IEC 60559),
- If the argument is ±0, -∞ is returned and FE_DIVBYZERO is raised.
- If the argument is 1, +0 is returned
- If the argument is negative, NaN is returned and FE_INVALID is raised.
- If the argument is +∞, +∞ is returned
- If the argument is NaN, NaN is returned
[edit] Notes
For integer arg
, the binary logarithm can be interpreted as the zero-based index of the most significant 1 bit in the input.
[edit] Example
Run this code
#include <iostream> #include <cmath> #include <cerrno> #include <cstring> #include <cfenv> #pragma STDC FENV_ACCESS ON int main() { std::cout << "log2(65536) = " << std::log2(65536) << '\n' << "log2(0.125) = " << std::log2(0.125) << '\n' << "log2(0x020f) = " << std::log2(0x020f) << " (highest set bit is in position 9)\n" << "base-5 logarithm of 125 = " << std::log2(125)/std::log2(5) << '\n'; // special values std::cout << "log2(1) = " << std::log2(1) << '\n' << "log2(+Inf) = " << std::log2(INFINITY) << '\n'; // error handling errno=0; std::feclearexcept(FE_ALL_EXCEPT); std::cout << "log2(0) = " << std::log2(0) << '\n'; if(errno == ERANGE) std::cout << " errno == ERANGE: " << std::strerror(errno) << '\n'; if(std::fetestexcept(FE_DIVBYZERO)) std::cout << " FE_DIVBYZERO raised\n"; }
Possible output:
log2(65536) = 16 log2(0.125) = -3 log2(0x020f) = 9.04166 (highest set bit is in position 9) base-5 logarithm of 125 = 3 log2(1) = 0 log2(+Inf) = inf log2(0) = -inf errno == ERANGE: Numerical result out of range FE_DIVBYZERO raised
[edit] See also
computes natural (base e) logarithm (to base e) (ln(x)) (function) |
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computes common (base 10) logarithm (log10(x)) (function) |
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(C++11)
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natural logarithm (to base e) of 1 plus the given number (ln(1+x)) (function) |
(C++11)
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returns 2 raised to the given power (2x) (function) |
C documentation for log2
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