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To represent shared or circular structures within a complex of Lisp objects, you can use the reader constructs ‘#n=’ and ‘#n#’.
Use #
n=
before an object to label it for later reference;
subsequently, you can use #
n#
to refer the same object in
another place. Here, n is some integer. For example, here is how
to make a list in which the first element recurs as the third element:
(#1=(a) b #1#)
This differs from ordinary syntax such as this
((a) b (a))
which would result in a list whose first and third elements look alike but are not the same Lisp object. This shows the difference:
(prog1 nil (setq x '(#1=(a) b #1#))) (eq (nth 0 x) (nth 2 x)) ⇒ t (setq x '((a) b (a))) (eq (nth 0 x) (nth 2 x)) ⇒ nil
You can also use the same syntax to make a circular structure, which appears as an element within itself. Here is an example:
#1=(a #1#)
This makes a list whose second element is the list itself. Here's how you can see that it really works:
(prog1 nil (setq x '#1=(a #1#))) (eq x (cadr x)) ⇒ t
The Lisp printer can produce this syntax to record circular and shared
structure in a Lisp object, if you bind the variable print-circle
to a non-nil
value. See Output Variables.