Creating a Basic Custom Schema Type
New in Mongoose 4.4.0: Mongoose supports custom types. Before you reach for a custom type, however, know that a custom type is overkill for most use cases. You can do most basic tasks with custom getters/setters, virtuals, and single embedded docs.
Let's take a look at an example of a basic schema type: a 1-byte integer.
To create a new schema type, you need to inherit from mongoose.SchemaType
and add the corresponding property to mongoose.Schema.Types
. The one
method you need to implement is the cast()
method.
function Int8(key, options) {
mongoose.SchemaType.call(this, key, options, 'Int8');
}
Int8.prototype = Object.create(mongoose.SchemaType.prototype);
// `cast()` takes a parameter that can be anything. You need to
// validate the provided `val` and throw a `CastError` if you
// can't convert it.
Int8.prototype.cast = function(val) {
var _val = Number(val);
if (isNaN(_val)) {
throw new mongoose.SchemaType.CastError('Int8',
val + ' is not a number');
}
_val = Math.round(_val);
if (_val < -0x80 || _val > 0x7F) {
throw new mongoose.SchemaType.CastError('Int8', val +
' is outside of the range of valid 8-bit ints');
}
return _val;
};
// Don't forget to add `Int8` to the type registry
mongoose.Schema.Types.Int8 = Int8;
var testSchema = new Schema({ test: Int8 });
var Test = mongoose.model('Test', testSchema);
var t = new Test();
t.test = 'abc';
assert.ok(t.validateSync());
assert.equal(t.validateSync().errors['test'].name, 'CastError');
assert.equal(t.validateSync().errors['test'].message,
'Cast to Int8 failed for value "abc" at path "test"');