Gets the Type of the current instance.
Syntax
Returns
The exact runtime type of the current instance.
Remarks
For two objects x and y that have identical runtime types, Object.ReferenceEquals(x.GetType(),y.GetType()) returns true. The following example uses the object.GetType method with the object.ReferenceEquals(object, object) method to determine whether one numeric value is the same type as two other numeric values.
code reference: System.Object.GetType#1
To determine whether an object is a specific type, you can use your language's type comparison keyword or construct. For example, you can use the TypeOf…Is construct in Visual Basic or the is keyword in C#.
The Type object exposes the metadata associated with the class of the current object.
Example
The following example demonstrates the fact that object.GetType returns the run-time type of the current instance:
C# Example
using System;
public class MyBaseClass: Object {
}
public class MyDerivedClass: MyBaseClass {
}
public class Test {
public static void Main() {
MyBaseClass myBase = new MyBaseClass();
MyDerivedClass myDerived = new MyDerivedClass();
object o = myDerived;
MyBaseClass b = myDerived;
Console.WriteLine("mybase: Type is {0}", myBase.GetType());
Console.WriteLine("myDerived: Type is {0}", myDerived.GetType());
Console.WriteLine("object o = myDerived: Type is {0}", o.GetType());
Console.WriteLine("MyBaseClass b = myDerived: Type is {0}", b.GetType());
}
}
The output is
mybase: Type is MyBaseClassmyDerived: Type is MyDerivedClass
object o = myDerived: Type is MyDerivedClass
MyBaseClass b = myDerived: Type is MyDerivedClass
Requirements
Assembly: mscorlib (in mscorlib.dll)
Assembly Versions: 1.0.5000.0, 2.0.0.0, 4.0.0.0