PHP 7.0.6 Released

class_alias

(PHP 5 >= 5.3.0, PHP 7)

class_aliasCreates an alias for a class

Description

bool class_alias ( string $original , string $alias [, bool $autoload = TRUE ] )

Creates an alias named alias based on the user defined class original. The aliased class is exactly the same as the original class.

Parameters

original

The original class.

alias

The alias name for the class.

autoload

Whether to autoload if the original class is not found.

Return Values

Returns TRUE on success or FALSE on failure.

Examples

Example #1 class_alias() example

<?php

class foo { }

class_alias('foo''bar');

$a = new foo;
$b = new bar;

// the objects are the same
var_dump($a == $b$a === $b);
var_dump($a instanceof $b);

// the classes are the same
var_dump($a instanceof foo);
var_dump($a instanceof bar);

var_dump($b instanceof foo);
var_dump($b instanceof bar);

?>

The above example will output:

bool(true)
bool(false)
bool(true)
bool(true)
bool(true)
bool(true)
bool(true)

See Also

User Contributed Notes

programmer-comfreek at hotmail dot com
4 years ago
If you defined the class 'original' in a namespace, you will have to specify the namespace(s), too:
<?php
namespace ns1\ns2\ns3;

class
A {}

class_alias('ns1\ns2\ns3\A', 'B');
/* or if you want B to exist in ns1\ns2\ns3 */
class_alias('ns1\ns2\ns3\A', 'ns1\ns2\ns3\B');
?>
mweierophinney at gmail dot com
3 years ago
class_alias() gives you the ability to do conditional imports.

Whereas the following will not work:

<?php
namespace Component;

if (
version_compare(PHP_VERSION, '5.4.0', 'gte')) {
    use
My\ArrayObject;
} else {
    use
ArrayObject;
}

class
Container extends ArrayObject
{
}
?>

the following, using class_alias, will:

<?php
namespace Component;

if (
version_compare(PHP_VERSION, '5.4.0', 'lt')) {
   
class_alias('My\ArrayObject', 'Component\ArrayObject');
} else {
   
class_alias('ArrayObject', 'Component\ArrayObject');
}

class
Container extends ArrayObject
{
}
?>

The semantics are slightly different (I'm now indicating that Container extends from an ArrayObject implementation in the same namespace), but the overall idea is the same: conditional imports.
nicolas dot grekas+php at gmail dot com
5 years ago
class_alias also works for interfaces!

<?php
interface foo {}
class_alias('foo', 'bar');
echo
interface_exists('bar') ? 'yes!' : 'no'; // prints yes!
?>
stanislav dot eckert at vizson dot de
7 months ago
class_alias() creates aliases only for user defined classes, not for classes supplied by PHP (PHP will show the warning "First argument of class_alias() must be a name of user defined class"). To create aliases for every kind of classes, use namespaces:

<?php

// Does not work
class_alias("ZipArchive", "myZip");

// Creates class alias "myZip" of class "ZipArchive"
use \ZipArchive as myZip;

?>
sergey dot karavay at gmail dot com
3 years ago
At first, you might wonder that:
<?php class A {}; class_alias('A', 'B'); ?>

is equivalent to:
<?php class A {}; class B extends A {}; ?>

class_alias is NOT equivalent to class extending! Private methods/properties are unseen in child classes, but in alias classes they are.
nicolas dot grekas+php at gmail dot com
5 years ago
At first, you might wonder that:
<?php class A {}; class_alias('A', 'B'); ?>

is equivalent to:
<?php class A {}; class B extends A {}; ?>

BUT when derivation creates a new class name - that means, you can then instantiate a new kind of objects - aliasing is just what it says: a synonym, so objects instantiated with the aliased name are of the exact same kind of objects instantiated with the non-aliased name.

See this code for example:
<?php
class A {};
class
B1 extends A {};
class_alias('A', 'B2');

$b1 = new B1; echo get_class($b1); // prints B1
$b2 = new B2; echo get_class($b2); // prints A !
?>
adam at adamhahn dot com
4 years ago
Something to note,

If the $original class has not yet been defined or loaded, the auto loader will be invoked in order to try and load it.

If the class for which you are trying to create an alias does not exist, or can not be loaded with the auto loader, you will generate a PHP Warning.
Anonymous
3 years ago
Like class_alias but for functions:

<?php
function function_alias ($original, $alias) {
 
 
$args = func_get_args();
 
assert('count($args) == 2', 'function_alias() require exactly two arguments');
 
assert('is_string($original) && is_string($alias)', 'function_alias() require string arguments');
 
 
// valid function name - http://php.net/manual/en/functions.user-defined.php
 
assert('preg_match(\'/^[a-zA-Z_\x7f-\xff][\\\\\\\\a-zA-Z0-9_\x7f-\xff]*$/\', $original) > 0',
   
"'$original' is not a valid function name");
 
assert('preg_match(\'/^[a-zA-Z_\x7f-\xff][\\\\\\\\a-zA-Z0-9_\x7f-\xff]*$/\', $alias) > 0',
   
"'$alias' is not a valid function name");
 
 
$aliasNamespace = substr($alias, 0, strrpos($alias, '\\') !== false ? strrpos($alias, '\\') : 0);
 
$aliasName = substr($alias, strrpos($alias, '\\') !== false ? strrpos($alias, '\\') + 1 : 0);
 
$serializedOriginal = var_export($original, true);
 
  eval(
"
    namespace
$aliasNamespace {
      function
$aliasName () {
        return call_user_func_array(
$serializedOriginal, func_get_args());
      }
    }
  "
);
 
}

?>

Until hopefully function_alias is added to php...
petar dot karan dot pk at gmail dot com
2 years ago
If you need the same function in PHP version < 5.3 you can use this

<?php
function class_alias($original,$alias) {
   
$newclass = create_function('','class '.$alias.' extends '.$original.' {}');
   
$newclass();
}
?>
paul [dot] kotets [at] gmail [dot] com
6 years ago
This function will appear in PHP 5.3 (at least I can use it with PHP 5.3, build Aug 7 2009 08:21:14)
For older versions of PHP I wrote the next function:

<?php
if (!function_exists('class_alias')) {
    function
class_alias($original, $alias) {
        eval(
'abstract class ' . $alias . ' extends ' . $original . ' {}');
    }
}
?>

Keyword 'abstract' is used for classes, which defines abstract methods.
This function is used in autoload purposes (when I extend classes), so abstract keyword doesn't broke anything for me.
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