std::is_partitioned
From cppreference.com
Defined in header
<algorithm>
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template< class InputIt, class UnaryPredicate >
bool is_partitioned( InputIt first, InputIt last, UnaryPredicate p ); |
(1) | (since C++11) |
template< class ExecutionPolicy, class InputIt, class UnaryPredicate >
bool is_partitioned( ExecutionPolicy&& policy, InputIt first, InputIt last, UnaryPredicate p ); |
(2) | (since C++17) |
1) Returns true if all elements in the range
[first, last)
that satisfy the predicate p
appear before all elements that don't. Also returns true if [first, last)
is empty.
2) Same as (1), but executed according to
policy
. This overload does not participate in overload resolution unless std::is_execution_policy_v<std::decay_t<ExecutionPolicy>> is true
Contents |
[edit] Parameters
first, last | - | the range of elements to check |
policy | - | the execution policy to use. See execution policy for details. |
p | - | unary predicate which returns true for the elements expected to be found in the beginning of the range. The signature of the predicate function should be equivalent to the following: bool pred(const Type &a); The signature does not need to have const &, but the function must not modify the objects passed to it. |
Type requirements | ||
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InputIt must meet the requirements of InputIterator .
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UnaryPredicate must meet the requirements of Predicate .
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[edit] Return value
true if the range [first, last)
is empty or is partitioned by p
. false otherwise.
[edit] Complexity
At most std::distance(first, last)
applications of p
.
[edit] Exceptions
The overload with a template parameter named ExecutionPolicy
reports errors as follows:
- If execution of a function invoked as part of the algorithm throws an exception,
-
- if
policy
is std::parallel_vector_execution_policy, std::terminate is called - if
policy
is std::sequential_execution_policy or std::parallel_execution_policy, the algorithm exits with an std::exception_list containing all uncaught exceptions. If there was only one uncaught exception, the algorithm may rethrow it without wrapping in std::exception_list. It is unspecified how much work the algorithm will perform before returning after the first exception was encountered. - if
policy
is some other type, the behavior is implementation-defined
- if
- If the algorithm fails to allocate memory (either for itself or to construct an std::exception_list when handling a user exception), std::bad_alloc is thrown.
[edit] Possible implementation
template< class InputIt, class UnaryPredicate > bool is_partitioned(InputIt first, InputIt last, UnaryPredicate p) { for (; first != last; ++first) if (!p(*first)) break; for (; first != last; ++first) if (p(*first)) return false; return true; } |
[edit] Example
Run this code
#include <algorithm> #include <array> #include <iostream> int main() { std::array<int, 9> v = { 1, 2, 3, 4, 5, 6, 7, 8, 9 }; auto is_even = [](int i){ return i % 2 == 0; }; std::cout.setf(std::ios_base::boolalpha); std::cout << std::is_partitioned(v.begin(), v.end(), is_even) << ' '; std::partition(v.begin(), v.end(), is_even); std::cout << std::is_partitioned(v.begin(), v.end(), is_even) << ' '; std::reverse(v.begin(), v.end()); std::cout << std::is_partitioned(v.begin(), v.end(), is_even); }
Output:
false true false
[edit] See also
divides a range of elements into two groups (function template) |
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(C++11)
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locates the partition point of a partitioned range (function template) |
(parallelism TS)
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parallelized version of std::is_partitioned (function template) |