std::lexicographical_compare
| Defined in header  <algorithm> | ||
| template< class InputIt1, class InputIt2 > bool lexicographical_compare( InputIt1 first1, InputIt1 last1, | (1) | |
| template< class ExecutionPolicy, class InputIt1, class InputIt2 > bool lexicographical_compare( ExecutionPolicy&& policy, InputIt1 first1, InputIt1 last1, | (2) | (since C++17) | 
| template< class InputIt1, class InputIt2, class Compare > bool lexicographical_compare( InputIt1 first1, InputIt1 last1, | (3) | |
| template< class ExecutionPolicy, class InputIt1, class InputIt2, class Compare > bool lexicographical_compare( ExecutionPolicy&& policy, InputIt1 first1, InputIt1 last1, | (4) | (since C++17) | 
Checks if the first range [first1, last1) is lexicographically less than the second range [first2, last2).
operator<.comp.policy. These overloads do not participate in overload resolution unless std::is_execution_policy_v<std::decay_t<ExecutionPolicy>> is trueLexicographical comparison is a operation with the following properties:
- Two ranges are compared element by element.
- The first mismatching element defines which range is lexicographically less or greater than the other.
- If one range is a prefix of another, the shorter range is lexicographically less than the other.
- If two ranges have equivalent elements and are of the same length, then the ranges are lexicographically equal.
- An empty range is lexicographically less than any non-empty range.
- Two empty ranges are lexicographically equal.
| Contents | 
[edit] Parameters
| first1, last1 | - | the first range of elements to examine | 
| first2, last2 | - | the second range of elements to examine | 
| policy | - | the execution policy to use. See execution policy for details. | 
| comp | - | comparison function object (i.e. an object that satisfies the requirements of Compare) which returns true if the first argument is less than the second.The signature of the comparison function should be equivalent to the following: bool cmp(const Type1 &a, const Type2 &b); The signature does not need to have const &, but the function object must not modify the objects passed to it. | 
| Type requirements | ||
| - InputIt1, InputIt2must meet the requirements ofInputIterator. | ||
[edit] Return value
true if the first range is lexicographically less than the second.
[edit] Complexity
At most 2·min(N1, N2) applications of the comparison operation, where N1 = std::distance(first1, last1) and N2 = std::distance(first2, last2).
[edit] Exceptions
The overloads with a template parameter named ExecutionPolicy report errors as follows:
- If execution of a function invoked as part of the algorithm throws an exception,
- 
-  if policyis std::parallel_vector_execution_policy, std::terminate is called
-  if policyis std::sequential_execution_policy or std::parallel_execution_policy, the algorithm exits with an std::exception_list containing all uncaught exceptions. If there was only one uncaught exception, the algorithm may rethrow it without wrapping in std::exception_list. It is unspecified how much work the algorithm will perform before returning after the first exception was encountered.
-  if policyis some other type, the behavior is implementation-defined
 
-  if 
- If the algorithm fails to allocate memory (either for itself or to construct an std::exception_list when handling a user exception), std::bad_alloc is thrown.
[edit] Possible implementation
| First version | 
|---|
| template<class InputIt1, class InputIt2> bool lexicographical_compare(InputIt1 first1, InputIt1 last1, InputIt2 first2, InputIt2 last2) { for ( ; (first1 != last1) && (first2 != last2); first1++, (void) first2++ ) { if (*first1 < *first2) return true; if (*first2 < *first1) return false; } return (first1 == last1) && (first2 != last2); } | 
| Second version | 
| template<class InputIt1, class InputIt2, class Compare> bool lexicographical_compare(InputIt1 first1, InputIt1 last1, InputIt2 first2, InputIt2 last2, Compare comp) { for ( ; (first1 != last1) && (first2 != last2); first1++, (void) first2++ ) { if (comp(*first1, *first2)) return true; if (comp(*first2, *first1)) return false; } return (first1 == last1) && (first2 != last2); } | 
[edit] Example
#include <algorithm> #include <iostream> #include <vector> #include <cstdlib> #include <ctime> int main() { std::vector<char> v1 {'a', 'b', 'c', 'd'}; std::vector<char> v2 {'a', 'b', 'c', 'd'}; std::srand(std::time(0)); while (!std::lexicographical_compare(v1.begin(), v1.end(), v2.begin(), v2.end())) { for (auto c : v1) std::cout << c << ' '; std::cout << ">= "; for (auto c : v2) std::cout << c << ' '; std::cout << '\n'; std::random_shuffle(v1.begin(), v1.end()); std::random_shuffle(v2.begin(), v2.end()); } for (auto c : v1) std::cout << c << ' '; std::cout << "< "; for (auto c : v2) std::cout << c << ' '; std::cout << '\n'; }
Possible output:
a b c d >= a b c d d a b c >= c b d a b d a c >= a d c b a c d b < c d a b
[edit] See also
| determines if two sets of elements are the same (function template) | |
| (parallelism TS) | parallelized version of std::lexicographical_compare(function template) |