std::lexicographical_compare
Defined in header
<algorithm>
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template< class InputIt1, class InputIt2 >
bool lexicographical_compare( InputIt1 first1, InputIt1 last1, |
(1) | |
template< class ExecutionPolicy, class InputIt1, class InputIt2 >
bool lexicographical_compare( ExecutionPolicy&& policy, InputIt1 first1, InputIt1 last1, |
(2) | (since C++17) |
template< class InputIt1, class InputIt2, class Compare >
bool lexicographical_compare( InputIt1 first1, InputIt1 last1, |
(3) | |
template< class ExecutionPolicy, class InputIt1, class InputIt2, class Compare >
bool lexicographical_compare( ExecutionPolicy&& policy, InputIt1 first1, InputIt1 last1, |
(4) | (since C++17) |
Checks if the first range [first1, last1) is lexicographically less than the second range [first2, last2).
operator<
.comp
.policy
. These overloads do not participate in overload resolution unless std::is_execution_policy_v<std::decay_t<ExecutionPolicy>> is trueLexicographical comparison is a operation with the following properties:
- Two ranges are compared element by element.
- The first mismatching element defines which range is lexicographically less or greater than the other.
- If one range is a prefix of another, the shorter range is lexicographically less than the other.
- If two ranges have equivalent elements and are of the same length, then the ranges are lexicographically equal.
- An empty range is lexicographically less than any non-empty range.
- Two empty ranges are lexicographically equal.
Contents |
[edit] Parameters
first1, last1 | - | the first range of elements to examine |
first2, last2 | - | the second range of elements to examine |
policy | - | the execution policy to use. See execution policy for details. |
comp | - | comparison function object (i.e. an object that satisfies the requirements of Compare ) which returns true if the first argument is less than the second. The signature of the comparison function should be equivalent to the following: bool cmp(const Type1 &a, const Type2 &b); The signature does not need to have const &, but the function object must not modify the objects passed to it. |
Type requirements | ||
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InputIt1, InputIt2 must meet the requirements of InputIterator .
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[edit] Return value
true if the first range is lexicographically less than the second.
[edit] Complexity
At most 2·min(N1, N2) applications of the comparison operation, where N1 = std::distance(first1, last1) and N2 = std::distance(first2, last2).
[edit] Exceptions
The overloads with a template parameter named ExecutionPolicy
report errors as follows:
- If execution of a function invoked as part of the algorithm throws an exception,
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- if
policy
is std::parallel_vector_execution_policy, std::terminate is called - if
policy
is std::sequential_execution_policy or std::parallel_execution_policy, the algorithm exits with an std::exception_list containing all uncaught exceptions. If there was only one uncaught exception, the algorithm may rethrow it without wrapping in std::exception_list. It is unspecified how much work the algorithm will perform before returning after the first exception was encountered. - if
policy
is some other type, the behavior is implementation-defined
- if
- If the algorithm fails to allocate memory (either for itself or to construct an std::exception_list when handling a user exception), std::bad_alloc is thrown.
[edit] Possible implementation
First version |
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template<class InputIt1, class InputIt2> bool lexicographical_compare(InputIt1 first1, InputIt1 last1, InputIt2 first2, InputIt2 last2) { for ( ; (first1 != last1) && (first2 != last2); first1++, (void) first2++ ) { if (*first1 < *first2) return true; if (*first2 < *first1) return false; } return (first1 == last1) && (first2 != last2); } |
Second version |
template<class InputIt1, class InputIt2, class Compare> bool lexicographical_compare(InputIt1 first1, InputIt1 last1, InputIt2 first2, InputIt2 last2, Compare comp) { for ( ; (first1 != last1) && (first2 != last2); first1++, (void) first2++ ) { if (comp(*first1, *first2)) return true; if (comp(*first2, *first1)) return false; } return (first1 == last1) && (first2 != last2); } |
[edit] Example
#include <algorithm> #include <iostream> #include <vector> #include <cstdlib> #include <ctime> int main() { std::vector<char> v1 {'a', 'b', 'c', 'd'}; std::vector<char> v2 {'a', 'b', 'c', 'd'}; std::srand(std::time(0)); while (!std::lexicographical_compare(v1.begin(), v1.end(), v2.begin(), v2.end())) { for (auto c : v1) std::cout << c << ' '; std::cout << ">= "; for (auto c : v2) std::cout << c << ' '; std::cout << '\n'; std::random_shuffle(v1.begin(), v1.end()); std::random_shuffle(v2.begin(), v2.end()); } for (auto c : v1) std::cout << c << ' '; std::cout << "< "; for (auto c : v2) std::cout << c << ' '; std::cout << '\n'; }
Possible output:
a b c d >= a b c d d a b c >= c b d a b d a c >= a d c b a c d b < c d a b
[edit] See also
determines if two sets of elements are the same (function template) |
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(parallelism TS)
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parallelized version of std::lexicographical_compare (function template) |