std::reverse
From cppreference.com
Defined in header
<algorithm>
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template< class BidirIt >
void reverse( BidirIt first, BidirIt last ); |
(1) | |
template< class ExecutionPolicy, class BidirIt >
void reverse( ExecutionPolicy&& policy, BidirIt first, BidirIt last ); |
(2) | (since C++17) |
1) Reverses the order of the elements in the range
[first, last)
Behaves as if applying std::iter_swap to every pair of iterators
first+i, (last-i) - 1
for each non-negative i < (last-first)/2
2) Same as (1), but executed according to
policy
. This overload does not participate in overload resolution unless std::is_execution_policy_v<std::decay_t<ExecutionPolicy>> is true
Contents |
[edit] Parameters
first, last | - | the range of elements to reverse |
policy | - | the execution policy to use. See execution policy for details. |
Type requirements | ||
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BidirIt must meet the requirements of BidirectionalIterator .
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-The type of dereferenced BidirIt must meet the requirements of Swappable .
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[edit] Return value
(none)
[edit] Exceptions
The overload with a template parameter named ExecutionPolicy
reports errors as follows:
- If execution of a function invoked as part of the algorithm throws an exception,
-
- if
policy
is std::parallel_vector_execution_policy, std::terminate is called - if
policy
is std::sequential_execution_policy or std::parallel_execution_policy, the algorithm exits with an std::exception_list containing all uncaught exceptions. If there was only one uncaught exception, the algorithm may rethrow it without wrapping in std::exception_list. It is unspecified how much work the algorithm will perform before returning after the first exception was encountered. - if
policy
is some other type, the behavior is implementation-defined
- if
- If the algorithm fails to allocate memory (either for itself or to construct an std::exception_list when handling a user exception), std::bad_alloc is thrown.
[edit] Possible implementation
template<class BidirIt> void reverse(BidirIt first, BidirIt last) { while ((first != last) && (first != --last)) { std::iter_swap(first++, last); } } |
[edit] Example
Run this code
#include <vector> #include <iostream> #include <iterator> #include <algorithm> int main() { std::vector<int> v({1,2,3}); std::reverse(std::begin(v), std::end(v)); std::cout << v[0] << v[1] << v[2] << '\n'; int a[] = {4, 5, 6, 7}; std::reverse(std::begin(a), std::end(a)); std::cout << a[0] << a[1] << a[2] << a[3] << '\n'; }
Output:
321 7654
[edit] Complexity
linear in the distance between first
and last
[edit] See also
creates a copy of a range that is reversed (function template) |
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(parallelism TS)
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parallelized version of std::reverse (function template) |