std::reverse
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                    | Defined in header  <algorithm> | ||
| template< class BidirIt > void reverse( BidirIt first, BidirIt last ); | (1) | |
| template< class ExecutionPolicy, class BidirIt > void reverse( ExecutionPolicy&& policy, BidirIt first, BidirIt last ); | (2) | (since C++17) | 
1) Reverses the order of the elements in the range 
[first, last)
 Behaves as if applying std::iter_swap to every pair of iterators 
first+i, (last-i) - 1 for each non-negative i < (last-first)/2
2) Same as (1), but executed according to 
policy. This overload does not participate in overload resolution unless std::is_execution_policy_v<std::decay_t<ExecutionPolicy>> is true| Contents | 
[edit] Parameters
| first, last | - | the range of elements to reverse | 
| policy | - | the execution policy to use. See execution policy for details. | 
| Type requirements | ||
| - BidirItmust meet the requirements ofBidirectionalIterator. | ||
| -The type of dereferenced BidirItmust meet the requirements ofSwappable. | ||
[edit] Return value
(none)
[edit] Exceptions
The overload with a template parameter named ExecutionPolicy reports errors as follows:
- If execution of a function invoked as part of the algorithm throws an exception,
- 
-  if policyis std::parallel_vector_execution_policy, std::terminate is called
-  if policyis std::sequential_execution_policy or std::parallel_execution_policy, the algorithm exits with an std::exception_list containing all uncaught exceptions. If there was only one uncaught exception, the algorithm may rethrow it without wrapping in std::exception_list. It is unspecified how much work the algorithm will perform before returning after the first exception was encountered.
-  if policyis some other type, the behavior is implementation-defined
 
-  if 
- If the algorithm fails to allocate memory (either for itself or to construct an std::exception_list when handling a user exception), std::bad_alloc is thrown.
[edit] Possible implementation
| template<class BidirIt> void reverse(BidirIt first, BidirIt last) { while ((first != last) && (first != --last)) { std::iter_swap(first++, last); } } | 
[edit] Example
Run this code
#include <vector> #include <iostream> #include <iterator> #include <algorithm> int main() { std::vector<int> v({1,2,3}); std::reverse(std::begin(v), std::end(v)); std::cout << v[0] << v[1] << v[2] << '\n'; int a[] = {4, 5, 6, 7}; std::reverse(std::begin(a), std::end(a)); std::cout << a[0] << a[1] << a[2] << a[3] << '\n'; }
Output:
321 7654
[edit] Complexity
linear in the distance between first and last
[edit] See also
| creates a copy of a range that is reversed (function template) | |
| (parallelism TS) | parallelized version of std::reverse(function template) |